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28 Mar 2013, 04:15
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In the solution provided,the max value of y is taken as 9 whereas the min value of x is taken as -3.Is this a mistake in the question or we can ignore < and consider it as <= ?
28 Mar 2013, 04:26
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We can solve it using this method:
−3<x<5 all *-1 = 3>-x>-5 = \(-5<-x<3\)
\(-7<y<9\)
We can sum the inequalities : \(-7-5<y-x<9+3 = -12<y-x<12\)
To answer your question, you can ignore the "<" and consider it "<=": it makes no difference.
−3<x<5 all *-1 = 3>-x>-5 = \(-5<-x<3\)
\(-7<y<9\)
We can sum the inequalities : \(-7-5<y-x<9+3 = -12<y-x<12\)
shreerajp99
To answer your question, you can ignore the "<" and consider it "<=": it makes no difference.
28 Mar 2013, 04:44
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shreerajp99
Range of y-x will be defined as least value of y-x, and greatest value of y-x
y-x will least when y has its smallest value and x has its greatest value. so y - x = -7 - 5 = -12
y-x will greatest when y has its greatest value and x has its least value. so y - x = 9 - (-3) = 9+3 = 12
So range y-x = -12 < y-x < 12 Choice D
Regards,
Abhijit
