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M27-20

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M27-20  [#permalink]

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New post 16 Sep 2014, 01:27
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A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

56% (00:40) correct 44% (00:49) wrong based on 242 sessions

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Math Expert
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Re M27-20  [#permalink]

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New post 16 Sep 2014, 01:27
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Re: M27-20  [#permalink]

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New post 28 Feb 2017, 14:53
|y| means y can be -y or +y. so x can be -x when y is negative and x is positive when y is positive. How is A the answer? I think it is E
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Re: M27-20  [#permalink]

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New post 28 Feb 2017, 21:19
Shiridip wrote:
|y| means y can be -y or +y. so x can be -x when y is negative and x is positive when y is positive. How is A the answer? I think it is E


Absolute value of a number is always non-negative. So, |y| (absolute value of y), regardless whether y itself is negative or positive, will be non-negative.

Please re-read the solution again:
(1) \(x*|y|\) is a prime number. Since only positive numbers can be primes, then: \(x*|y|=positive\) hence \(x=positive\). Sufficient.
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Re: M27-20  [#permalink]

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New post 23 Nov 2018, 22:12
Bunuel wrote:
Shiridip wrote:
|y| means y can be -y or +y. so x can be -x when y is negative and x is positive when y is positive. How is A the answer? I think it is E


Absolute value of a number is always non-negative. So, |y| (absolute value of y), regardless whether y itself is negative or positive, will be non-negative.

Please re-read the solution again:
(1) \(x*|y|\) is a prime number. Since only positive numbers can be primes, then: \(x*|y|=positive\) hence \(x=positive\). Sufficient.

Hi Bunuel , I have the same issue .Can you please elaborate a little more . If y is negative then |y| =-y and if y is positive then |y| =y. Please let me know if this is incorrect
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Re: M27-20   [#permalink] 23 Nov 2018, 22:12
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M27-20

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