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Bunuel
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NatalieStarr
Bunuel
I understand the arrangement of the equation made above but I was considering the following:
(1) if a>0, a=-b; -b+b=0
BUT if a<0, -a=-b; a=b; and then the sum is a+a=2a (or b+b=2b)
in this case the answer would be not sufficient. Where is the mistake here?
Thank you

If a > 0 and b > 0, then |a| = -|b| transforms to a = -b --> a + b = 0. This case is not possible: the sum of two positive values cannot be 0.
If a > 0 and b < 0, then |a| = -|b| transforms to a = -(-b) --> a = b. This case is not possible: positive a (a > 0) cannot equal to negative b (b < 0).
If a < 0 and b < 0, then |a| = -|b| transforms to -a = -(-b) --> a + b = 0. This case is not possible: the sum of two negative values cannot be 0.
If a < 0 and b > 0, then |a| = -|b| transforms to -a = -b --> a = b. This case is not possible: negative a (a < 0) cannot equal to positive b (b > 0).

The only case left is a = b = 0.
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I think this is a high-quality question and I agree with explanation.
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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