(1) The sum of ANY two factors of \(x^2\) is even.
Let x be 3. So \(x^2 = 9\). Sum of any two factors of 9 is even. The minimum value x can take is 3. As y>1, \(x^y = 3^y\) and the minimum value of \(x^y\) is 9 which is greater than 8.
SUFFICIENT.
(2) The product of ANY two factors of \(y^3\) is odd.
Let y=3, \(y^3 = 27\). The product of any two factors of y is odd.
\(x^y = x^3\)
Now if x = 2, then \(x^y = 8\). The answer to the question is NO
If x = 3, \(x^y > 8\). The answer to the question is YES.
INSUFFICIENT.
OPTION:
A
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Regards,
Chaitanya
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