Can we take this approach?

BunuelThe equations are

x=3y+z [ Constraints: y>z and z>=0] As Remainder is greater than Quotient.

z=ay+2 [ Constraints: y>2]

Thus,

x=3y+ay+2

x=y(a+3) + 2

x=3y+2 or x =4y+2 or x=5y+2 [a can take values 0,1,2,3...]

Looking at the options:

I. 5 Can only fit if y=1, which breaks constraint of y>2, so NO

II. 8 Can only fit if y=2, which breaks constraint of y>2, so NO

III. 32 Fits the equation x=3*10+2 or x=5*6+2 So YES