GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 16 Oct 2019, 19:57

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

M30-17

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Find Similar Topics 
Intern
Intern
avatar
B
Joined: 19 Apr 2018
Posts: 2
Re: M30-17  [#permalink]

Show Tags

New post 26 Dec 2018, 04:07
Can we take this approach? Bunuel
The equations are
x=3y+z [ Constraints: y>z and z>=0] As Remainder is greater than Quotient.
z=ay+2 [ Constraints: y>2]
Thus,
x=3y+ay+2
x=y(a+3) + 2
x=3y+2 or x =4y+2 or x=5y+2 [a can take values 0,1,2,3...]

Looking at the options:
I. 5 Can only fit if y=1, which breaks constraint of y>2, so NO
II. 8 Can only fit if y=2, which breaks constraint of y>2, so NO
III. 32 Fits the equation x=3*10+2 or x=5*6+2 So YES
Manager
Manager
avatar
B
Joined: 24 Dec 2011
Posts: 52
Location: India
GPA: 4
WE: General Management (Health Care)
M30-17  [#permalink]

Show Tags

New post 18 Jan 2019, 10:48
very nice question..
thank you for posting this. decent explanation.

Got a li'l doubt. same line of thinking as i came to y>2 bt substituted z in the first equation and tried to solve.
I got the equation x=3y+z
substituting z=y+2
comes to x=4y+2. (and y>2)
I'm not getting 32 either
_________________
------
A Reader lives a thousand lives before he dies. The one who doesn't read lives only one..
the great thing abt reading is that it broadens ur Life..


Kudos is the best way to say Thank you! Please give me a kudos if you like my post
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 58381
Re: M30-17  [#permalink]

Show Tags

New post 19 Jan 2019, 01:19
1
venkivety wrote:
very nice question..
thank you for posting this. decent explanation.

Got a li'l doubt. same line of thinking as i came to y>2 bt substituted z in the first equation and tried to solve.
I got the equation x=3y+z
substituting z=y+2
comes to x=4y+2. (and y>2)
I'm not getting 32 either


When z is divided by y, the remainder is 2 does not mean that z=y+2. It means that z =yq + 2.

Check the solution:
When \(z\) is divided by \(y\), the remainder is 2: when divisor (\(y\) in our case) is more than dividend (\(z\) in our case), then the reminder equals to the dividend (for example, 2 divided by 5 gives the remainder of 2). Therefore, \(z=2\) and \(2 < y\).

So, we have that \(x=3y+2\) and \(2 < y\). This implies that the least value of \(x\) is \(x=3*3+2=11\): \(x\) cannot be 5 or 8.

Could \(x\) be 32? Yes. If \(y=10\), then \(x=3*10+2=32\).
_________________
Manager
Manager
avatar
B
Joined: 24 Dec 2011
Posts: 52
Location: India
GPA: 4
WE: General Management (Health Care)
M30-17  [#permalink]

Show Tags

New post 19 Jan 2019, 11:20
Bunuel wrote:
venkivety wrote:
very nice question..
thank you for posting this. decent explanation.

Got a li'l doubt. same line of thinking as i came to y>2 bt substituted z in the first equation and tried to solve.
I got the equation x=3y+z
substituting z=y+2
comes to x=4y+2. (and y>2)
I'm not getting 32 either


When z is divided by y, the remainder is 2 does not mean that z=y+2. It means that z =yq + 2.

Check the solution:
When \(z\) is divided by \(y\), the remainder is 2: when divisor (\(y\) in our case) is more than dividend (\(z\) in our case), then the reminder equals to the dividend (for example, 2 divided by 5 gives the remainder of 2). Therefore, \(z=2\) and \(2 < y\).

So, we have that \(x=3y+2\) and \(2 < y\). This implies that the least value of \(x\) is \(x=3*3+2=11\): \(x\) cannot be 5 or 8.

Could \(x\) be 32? Yes. If \(y=10\), then \(x=3*10+2=32\).


thanq very much 4 the reply..
cleared..
_________________
------
A Reader lives a thousand lives before he dies. The one who doesn't read lives only one..
the great thing abt reading is that it broadens ur Life..


Kudos is the best way to say Thank you! Please give me a kudos if you like my post
GMAT Club Bot
M30-17   [#permalink] 19 Jan 2019, 11:20

Go to page   Previous    1   2   [ 24 posts ] 

Display posts from previous: Sort by

M30-17

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  

Moderators: chetan2u, Bunuel






cron

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne