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26 May 2017, 04:43
Kudos
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On the x-y plane there are 5 line segments that have different angles shown as the above figure. If 2 line segments are randomly selected from the 5 line segments, how many angles can be formed from the selection of 2 line segments?
A. 8
B. 10
C. 12
D. 15
E. 18
26 May 2017, 04:46
Kudos
Bookmarks
Official Solution:
On the x-y plane there are 5 line segments that have different angles shown as the above figure. If 2 line segments are randomly selected from the 5 line segments, how many angles can be formed from the selection of 2 line segments?
A. 8
B. 10
C. 12
D. 15
E. 18
In general, for probability questions, \(_{n}C_{r}\) (combination) appears more frequently than \(_{n}P_{r}\) (permutation). This question is also a \(_{n}C_{r}\) question. If you select 2 lines, you are able to know the angle in between the lines, so there are 5 lines. When you select 2 lines from the five lines, you get \(_{5}C_{2}=\frac{(5)(4)}{2!} = 10\). Therefore, the answer is B.
Answer: B
On the x-y plane there are 5 line segments that have different angles shown as the above figure. If 2 line segments are randomly selected from the 5 line segments, how many angles can be formed from the selection of 2 line segments?
A. 8
B. 10
C. 12
D. 15
E. 18
In general, for probability questions, \(_{n}C_{r}\) (combination) appears more frequently than \(_{n}P_{r}\) (permutation). This question is also a \(_{n}C_{r}\) question. If you select 2 lines, you are able to know the angle in between the lines, so there are 5 lines. When you select 2 lines from the five lines, you get \(_{5}C_{2}=\frac{(5)(4)}{2!} = 10\). Therefore, the answer is B.
Answer: B
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