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When 120 candies are given to 25 children and the maximum number of candies for each child is 7, what is the maximum number of children who get only 1 candy?
When 120 candies are given to 25 children and the maximum number of candies for each child is 7, what is the maximum number of children who get only 1 candy?
A. 5 B. 6 C. 7 D. 8 E. 9
120 candies are given to children, and the maximum number of candies for each child is 7, so
\(120 = 7*17+1*1 (17 + 1 = 18)\), and this cannot satisfy the question because there are only 18 children. \(120 = 7*16+1*1+1*1+1*1+1*1+1*1+1*1+1*1+1*1\) \((16+1+1+1+1+1+1+1+1=24)\), and this also cannot satisfy the question because there are only 24 children.
When \(120 = 7*15+6*1+1*1+1*1+1*1+1*1+1*1+1*1+1*1+1*1+1*1 = 120\)
\((15+1+1+1+1+1+1+1+1+1+1 = 25)\), it satisfies the question because there are 25 children.
In other words, 15 children are each given 7 candies, 1 child is given 6 candies, and the rest of the 9 children only get 1 candy each. Hence, the maximum number of children who get 1 candy is \(1*1+1*1+1*1+1*1+1*1+1*1+1*1+1*1+1*1\), then \(1+1+1+1+1+1+1+1+1 = 9\). Therefore, the answer is E.