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04 Jul 2019, 06:56
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If \(x\) is a negative integer and \(2 < x^2 < 36\), what is the least possible value of \(|2x + 11|\)?
A. 7
B. 5
C. 3
D. 1
E. 0
A. 7
B. 5
C. 3
D. 1
E. 0
04 Jul 2019, 06:56
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Official Solution:
If \(x\) is a negative integer and \(2 < x^2 < 36\), what is the least possible value of \(|2x + 11| \)?
A. 7
B. 5
C. 3
D. 1
E. 0
Notice that we are told that \(x\) is a negative integer. This means \(x\) can be -2, -3, -4, or -5. The least value of \(|2x + 11|\) for these values of \(x\) is 1, when \(x=-5\).
If we were not told that \(x\) is a negative integer, the least value would obviously be 0, for \(x=-5.5\).
Answer: D
If \(x\) is a negative integer and \(2 < x^2 < 36\), what is the least possible value of \(|2x + 11| \)?
A. 7
B. 5
C. 3
D. 1
E. 0
Notice that we are told that \(x\) is a negative integer. This means \(x\) can be -2, -3, -4, or -5. The least value of \(|2x + 11|\) for these values of \(x\) is 1, when \(x=-5\).
If we were not told that \(x\) is a negative integer, the least value would obviously be 0, for \(x=-5.5\).
Answer: D
30 Oct 2019, 09:44
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Hi Bunuel!
Can i write inequality as 2^1/2<x<6
-6<-x<-2^1/2 hence take least value for x=-6
Can i write inequality as 2^1/2<x<6
-6<-x<-2^1/2 hence take least value for x=-6
