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Bunuel
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knowledgeispowerr
I think this is really unclear because it would be logical to think that the remainder includes the soda. i dont think the question is worded clearly sorry

Not sure I understand what you're trying to say there!

Luis spent $72 in the supermarket:

  • A third on fruits, which is $24.
  • A sixth on vegetables, making it $12.
  • Directly, $12 on pasta.

This leaves us with a remainder of $72 - $24 - $12 - $12 = $24.

From this, half ($12) was spent on chocolate.

The soda expense was equal to the vegetable spend, which is $12.

So:
Fruits ($24) +
Vegetables ($12) +
Pasta ($12) +
Chocolate ($12) +
Soda ($12)
= $72.
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­Given - Luis spent a certain amount of money in a supermarket. He spent a third of the money on fruits, a sixth on vegetables, $12 on pasta, half the remainder of the money on chocolate, and as much on soda as he spent on vegetables.
To find - How much money did Luis spend in the supermarket?
In given data it says \(\frac{1}{3}\)th and \(\frac{1}{6}\)th­
So i am taking LCM in terms of multiple of 6 as \(24x\)
He spent a third of the money on fruits = \(8x\)
a sixth on vegetables = \(4x\)
$12 on pasta = \(12\)
half the remainder of the money on chocolate = \(\frac{1}{2} * (24x-12x-12) = \frac{1}{2} * (12x-12) = 6x-6\)
and as much on soda as he spent on vegetables =­ \(4x\)
Total spendings \(= 24x = 8x + 4x + 12 + 6x - 6 + 4x = 22x + 6\)
2x = 6
x=3
Therefore total spendings = \(24x = 24*3 = 72\)
Answer C.­
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