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Bunuel
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Hello ,
Selling price =120(1+2x/100)
selling price =210(1-x/100)

so when we equate both equation

210(1-x/100)=120(1+2x/100)
900=45x
Hence x = 20

Hence option B is correct
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MAN11
profit = SP - CP, why we are not subtracting the cost price?
Bunuel
Official Solution:

A pawn shop purchased a bracelet for $120 and listed it for $210. However, the bracelet was sold at a discount of \(x\) percent off the listed price. If the shop made a profit of \(2x\) percent on the cost price, what is the value of \(x\)?

A. 15
B. 20
C. 25
D. 30
E. 40


Given that the bracelet was sold at a discount of \(x\) percent off the listed price, the actual selling price was \(210(1 - \frac{x}{100})\).

Given that the shop made a profit of \(2x\) percent on the cost price, the relationship can be represented as \(120(1 + \frac{2x}{100}) = 210(1 - \frac{x}{100})\):

\(4(\frac{100+2x}{100})=7(\frac{100 - x}{100})\)

\(4(100+2x)=7(100 - x)\)

\(400+8x=700 - 7x\)

\(15x=300\)

\(x=20\)

Answer: B

Instead of writing profit as SP - CP, the solution uses the percentage form: SP = CP * (1 + profit%). Since profit is 2x% and CP is 120, that gives SP = 120 * (1 + 2x/100). This is then set equal to the discounted selling price, 210 * (1 - x/100). So it's just a different, equivalent way of using the cost price.
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Bunuel

I really need your take on the following:

The actual selling price is $210(1−x/100)

The Cost is $120

The Profit is $120(1+2x/100)

The formula for calculating the profit:

Profit= Revenue - Cost

$120(1+2x/100)= $210(1−x/100) - $120

Why do you skip the $120 cost in your calculation of the profit and just equate the Profit to the selling price???


Thanks in advance!
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Rebaz
Bunuel

I really need your take on the following:

The actual selling price is $210(1−x/100)

The Cost is $120

The Profit is $120(1+2x/100)

The formula for calculating the profit:

Profit= Revenue - Cost

$120(1+2x/100)= $210(1−x/100) - $120

Why do you skip the $120 cost in your calculation of the profit and just equate the Profit to the selling price???


Thanks in advance!

Check here: https://gmatclub.com/forum/m39-430759.html#p3557172
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