Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jul 1206:30 AM PDT
-08:30 AM PDT
Join our webinar to master GMAT RC Main Point Questions! Learn effective strategies to decipher passage themes and purposes. Senior Verbal Expert- Sunita Singhvi will equip you with tools to navigate complexities and avoid common traps set by the GMAT.
Jul 1211:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test.
Jun 3008:00 AM PDT
-11:59 PM PDT
Join us June 30th for 2 weeks of GMAT questions (just 8 per day) to help with your prep and to compete with your fellow GMAT Clubbers for a chance to win a prize fund of $30,000 for you and your team-mates!
Jul 0901:00 PM EDT
-02:00 PM EDT
More Target Test Prep students are earning 100th percentile GMAT scores. Don’t settle for less when the Target Test Prep course gives you everything you need to score high on the GMAT. Start your 5-day free trial today.
Jul 1311:00 AM EDT
-12:30 PM EDT
Looking for your GMAT motivation to break through the score plateau? Pragati improved her score by massive 160 points with strategic guidance and hard-work! Find out how personalized mentorship and a strong mindset can turn GMAT struggles into success.
Jul 1508:00 PM PDT
-09:00 PM PDT
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Jul 1611:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
29 Jul 2024, 07:43
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
48% (03:00) correct
52%
(02:04)
wrong
based on 29
sessions
History
Date
Time
Result
Not Attempted Yet
A mixture of orange and carrot juices consists of \(x\) liters of orange juice and \(y\) liters of carrot juice. What percent of the mixture, by volume, is orange juice?
(1) If 2 liters of carrot juice were replaced with 2 liters of orange juice, the percentage of orange juice by volume in the mixture would double.
(2) If half of the carrot juice by volume were replaced with an equal amount of orange juice, the percentage of orange juice by volume in the mixture would double.
(1) If 2 liters of carrot juice were replaced with 2 liters of orange juice, the percentage of orange juice by volume in the mixture would double.
(2) If half of the carrot juice by volume were replaced with an equal amount of orange juice, the percentage of orange juice by volume in the mixture would double.
29 Jul 2024, 07:43
Kudos
Bookmarks
Official Solution:
A mixture of orange and carrot juices consists of \(x\) liters of orange juice and \(y\) liters of carrot juice. What percent of the mixture, by volume, is orange juice?
Essentially, the question asks to find the value of \(\frac{x}{x + y}*100\).
(1) If 2 liters of carrot juice were replaced with 2 liters of orange juice, the percentage of orange juice by volume in the mixture would double.
This operation increases the amount of orange juice by 2 liters while keeping the total volume the same. This implies that 2 liters is enough to double the original percentage, meaning the original amount of orange juice must also be 2 liters. However, without knowing the value of \(y\), we cannot calculate \(\frac{2}{2 + y} * 100\). Not sufficient.
* For those preferring algebra, here is what this statement means:
\(\frac{x + 2}{x + y} * 100= 2p\).
Since \(\frac{x}{x + y} * 100= p\), then:
\(\frac{x + 2}{x + y} * 100= 2(\frac{x}{x + y} * 100)\)
\(x + 2 = 2x\)
\(x =2\).
(2) If half of the carrot juice by volume were replaced with an equal amount of orange juice, the percentage of orange juice by volume in the mixture would double.
This operation implies that replacing \(\frac{y}{2}\) liters of carrot juice with \(\frac{y}{2}\) liters of orange juice doubles the percentage of orange juice in the mixture. By the same logic as above, we can infer that \(x = \frac{y}{2}\), which gives \(y = 2x\). Therefore, \(\frac{x}{x + y}*100 = \frac{x}{x + 2x} * 100 = 33 \frac{1}{3}\%\). Sufficient.
* For those preferring algebra, here is what this statement means:
\(\frac{x + \frac{y}{2}}{x + y} * 100= 2p\).
Since \(\frac{x}{x + y}*100=p\), then:
\(\frac{x + \frac{y}{2}}{x + y} * 100= 2(\frac{x}{x + y} * 100)\)
\(x +\frac{y}{2}= 2x\)
\(y =2x\).
Answer: B
A mixture of orange and carrot juices consists of \(x\) liters of orange juice and \(y\) liters of carrot juice. What percent of the mixture, by volume, is orange juice?
Essentially, the question asks to find the value of \(\frac{x}{x + y}*100\).
(1) If 2 liters of carrot juice were replaced with 2 liters of orange juice, the percentage of orange juice by volume in the mixture would double.
This operation increases the amount of orange juice by 2 liters while keeping the total volume the same. This implies that 2 liters is enough to double the original percentage, meaning the original amount of orange juice must also be 2 liters. However, without knowing the value of \(y\), we cannot calculate \(\frac{2}{2 + y} * 100\). Not sufficient.
* For those preferring algebra, here is what this statement means:
\(\frac{x + 2}{x + y} * 100= 2p\).
Since \(\frac{x}{x + y} * 100= p\), then:
\(\frac{x + 2}{x + y} * 100= 2(\frac{x}{x + y} * 100)\)
\(x + 2 = 2x\)
\(x =2\).
(2) If half of the carrot juice by volume were replaced with an equal amount of orange juice, the percentage of orange juice by volume in the mixture would double.
This operation implies that replacing \(\frac{y}{2}\) liters of carrot juice with \(\frac{y}{2}\) liters of orange juice doubles the percentage of orange juice in the mixture. By the same logic as above, we can infer that \(x = \frac{y}{2}\), which gives \(y = 2x\). Therefore, \(\frac{x}{x + y}*100 = \frac{x}{x + 2x} * 100 = 33 \frac{1}{3}\%\). Sufficient.
* For those preferring algebra, here is what this statement means:
\(\frac{x + \frac{y}{2}}{x + y} * 100= 2p\).
Since \(\frac{x}{x + y}*100=p\), then:
\(\frac{x + \frac{y}{2}}{x + y} * 100= 2(\frac{x}{x + y} * 100)\)
\(x +\frac{y}{2}= 2x\)
\(y =2x\).
Mustafa10102175
02 Aug 2024, 05:53
Kudos
Bookmarks
I think this is a high-quality question
