Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 1612:00 PM EDT
-11:59 PM EDT
You’re first to know: Save $200 on GMAT prep starting tomorrow, 4/13. Get 6 official practice tests and study with real questions. Be ready to save!
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
12 Jan 2026, 11:17
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
(N/A)
Question Stats:
100% (03:55) correct
0%
(00:00)
wrong
based on 1
sessions
History
Date
Time
Result
Not Attempted Yet
At 9:00 AM, a man and his dog leave their home and walk along the same path toward a park. The man walks at a constant speed, while the dog runs at a faster constant speed. The dog reaches the park at 9:30 AM, spends 20 minutes playing with other dogs, and then runs back toward the man at its usual constant rate. They meet at 10:00 AM, and from there, both walk together at the man’s speed to the park. When will the man reach the park?
A. 10:10 AM
B. 10:15 AM
C. 10:20 AM
D. 10:30 AM
E. 10:40 AM
A. 10:10 AM
B. 10:15 AM
C. 10:20 AM
D. 10:30 AM
E. 10:40 AM
12 Jan 2026, 11:17
Kudos
Bookmarks
Official Solution:
At 9:00 AM, a man and his dog leave their home and walk along the same path toward a park. The man walks at a constant speed, while the dog runs at a faster constant speed. The dog reaches the park at 9:30 AM, spends 20 minutes playing with other dogs, and then runs back toward the man at its usual constant rate. They meet at 10:00 AM, and from there, both walk together at the man’s speed to the park. When will the man reach the park?
A. 10:10 AM
B. 10:15 AM
C. 10:20 AM
D. 10:30 AM
E. 10:40 AM
When the man and the dog meet at 10:00 AM, the man has been walking for 60 minutes, while the dog has been running from 9:50 AM to 10:00 AM for 10 minutes. The distance from home to the park is the total distance covered by the man in 60 minutes and the dog in 10 minutes.
We know the dog covered the entire distance to the park in 30 minutes, so in 10 minutes, the dog would have covered one-third of this distance. This means that in 60 minutes, the man covered two-thirds of the distance to the park.
If the man covers two-thirds of the distance in 60 minutes, it would take him 90 minutes to cover the entire distance. Therefore, the man will reach the park at 9:00 AM plus 90 minutes, which means he will arrive at 10:30 AM.
Answer: D
At 9:00 AM, a man and his dog leave their home and walk along the same path toward a park. The man walks at a constant speed, while the dog runs at a faster constant speed. The dog reaches the park at 9:30 AM, spends 20 minutes playing with other dogs, and then runs back toward the man at its usual constant rate. They meet at 10:00 AM, and from there, both walk together at the man’s speed to the park. When will the man reach the park?
A. 10:10 AM
B. 10:15 AM
C. 10:20 AM
D. 10:30 AM
E. 10:40 AM
When the man and the dog meet at 10:00 AM, the man has been walking for 60 minutes, while the dog has been running from 9:50 AM to 10:00 AM for 10 minutes. The distance from home to the park is the total distance covered by the man in 60 minutes and the dog in 10 minutes.
We know the dog covered the entire distance to the park in 30 minutes, so in 10 minutes, the dog would have covered one-third of this distance. This means that in 60 minutes, the man covered two-thirds of the distance to the park.
If the man covers two-thirds of the distance in 60 minutes, it would take him 90 minutes to cover the entire distance. Therefore, the man will reach the park at 9:00 AM plus 90 minutes, which means he will arrive at 10:30 AM.
Answer: D
04 Mar 2026, 03:28
Kudos
Bookmarks
Woah great question. Definitely worth 800+ purely because of the visualisation required to get to an elegant solution.
I took lot of time and did the algebraic method and landed at 30mins from 10 or 10:30.
We get multiple relations with D for both dog and the man
We eventually landed up with a speed relation that dog's speed is 3x that of the man's.
On resubstituting we land up with 1.5-1 from 10am or 0.5hrs or 30 mins.
I took lot of time and did the algebraic method and landed at 30mins from 10 or 10:30.
We get multiple relations with D for both dog and the man
We eventually landed up with a speed relation that dog's speed is 3x that of the man's.
On resubstituting we land up with 1.5-1 from 10am or 0.5hrs or 30 mins.
Bunuel
