Official Solution: Three buses leave Riverton and travel along the same route toward Lakeview. Bus 1 leaves first and travels at a constant speed of 50 km/h. Bus 2 leaves Riverton 6 hours after Bus 1 and travels at a constant speed of 80 km/h. Bus 3 also leaves Riverton after Bus 1 and travels at a constant speed of 100 km/h. If Bus 2 and Bus 3 catch up to Bus 1 at the same time, how many hours after Bus 1 leaves does Bus 3 leave? A. 2
B. 6
C. 8
D. 10
E. 16
Bus 2 leaves 6 hours after Bus 1, so by the time Bus 2 starts, Bus 1 has traveled:
\(6 * 50 = 300\) km
Thus, Bus 1 has a 300 km lead.
To catch Bus 1, Bus 2 needs:
\(\text{time} = \frac{\text{distance}}{\text{relative speed}} = \frac{300}{80 - 50} = 10\) hours
So Bus 2 catches Bus 1:
\(6 + 10 = 16\) hours
after Bus 1 leaves.
In 16 hours, Bus 1 travels:
\(16 * 50 = 800\) km
Since Bus 3 catches Bus 1 at the same time, Bus 3 must also travel 800 km before catching Bus 1.
At 100 km/h, Bus 3 needs:
\(\frac{800}{100} = 8\) hours
Therefore, Bus 3 must have left:
\(16 - 8 = 8\) hours
after Bus 1 left.
Answer: C