Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Aug 2710:00 AM EDT
-11:00 AM EDT
We’ve worked incredibly hard to build TTP into the best test prep experience possible, and it would mean a lot to us to win Newsweek’s 2026 Readers’ Choice Award for Best Test Prep. If TTP has helped you, we’d be incredibly grateful for your vote.
Sep 0201:00 PM EDT
-11:59 PM EDT
Take 30% off all study plans with code COURSEWORK - Expires on Monday 9/7
Sep 0410:00 AM PDT
-11:00 AM PDT
What does test anxiety really look like on the GMAT? For many test takers, it does not look like a panic attack. Instead, it shows up as brain fog, rereading, negative comparisons, mental noise....
Sep 0609:30 AM EDT
-12:30 PM EST
Top scores are possible when you enroll in a powerful EA course, taught live online + 6 months access to TTP OnDemand video courses included! Perfect class schedule and easy course access for working professionals. Class starts Sundays Sept. 6, 2026.- Sep 07
12:01 AM PDT
-11:59 PM PDT
On the 7th, GMAT Club Tests will be Free! Including all the Quizzes, Questions, and Tests. 12 AM - 11:59 PM PDT - Sep 09
07:00 AM PDT
-10:00 AM PDT
Meet AdComs and explore top Master’s programs - MiM, MiF, MSc, MSBA and more. - Application Fee Waivers - Free 1-Week of GMAT Club Tests: - Master's Application Toolkit - Grand Prize Giveaway 
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 2108:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
03 Aug 2026, 10:11
Kudos
Bookmarks
At a museum, all visitors in a certain tour group were either students or teachers. Some visitors rented audio guides, and the rest did not. If 12 students did not rent audio guides, whereas 24 teachers did rent audio guides, how many teachers were in the tour group?
(1) The number of students who rented audio guides was twice the number of teachers who did not rent audio guides.
(2) The total number of visitors in the group who rented audio guides was twice the total number of visitors who did not rent audio guides.
(1) The number of students who rented audio guides was twice the number of teachers who did not rent audio guides.
(2) The total number of visitors in the group who rented audio guides was twice the total number of visitors who did not rent audio guides.
03 Aug 2026, 10:11
Kudos
Bookmarks
Official Solution:
At a museum, all visitors in a certain tour group were either students or teachers. Some visitors rented audio guides, and the rest did not. If 12 students did not rent audio guides, whereas 24 teachers did rent audio guides, how many teachers were in the tour group?
Let:
students who rented audio guides \(= x\)
teachers who did not rent \(= y\)
The question asks for the total number of teachers: \(24 + y\).
(1) The number of students who rented audio guides was twice the number of teachers who did not rent audio guides.
This implies \(x = 2y\).
But we still do not know \(y\), so we cannot find \(24 + y\). Not sufficient.
(2) The total number of visitors in the group who rented audio guides was twice the total number of visitors who did not rent audio guides.
This implies:
\(x + 24 = 2(12 + y)\)
\(x = 2y\)
This is exactly the same information as in statement (1). So we still cannot find \(y\), and therefore we cannot find the total number of teachers. Not sufficient.
(1) + (2) Together, the two statements still give only \(x = 2y\). So the total number of teachers, \(24 + y\), still cannot be determined. Not sufficient.
Answer: E
At a museum, all visitors in a certain tour group were either students or teachers. Some visitors rented audio guides, and the rest did not. If 12 students did not rent audio guides, whereas 24 teachers did rent audio guides, how many teachers were in the tour group?
Let:
students who rented audio guides \(= x\)
teachers who did not rent \(= y\)
The question asks for the total number of teachers: \(24 + y\).
(1) The number of students who rented audio guides was twice the number of teachers who did not rent audio guides.
This implies \(x = 2y\).
But we still do not know \(y\), so we cannot find \(24 + y\). Not sufficient.
(2) The total number of visitors in the group who rented audio guides was twice the total number of visitors who did not rent audio guides.
This implies:
\(x + 24 = 2(12 + y)\)
\(x = 2y\)
This is exactly the same information as in statement (1). So we still cannot find \(y\), and therefore we cannot find the total number of teachers. Not sufficient.
(1) + (2) Together, the two statements still give only \(x = 2y\). So the total number of teachers, \(24 + y\), still cannot be determined. Not sufficient.
Answer: E
