Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Aug 2710:00 AM EDT
-11:00 AM EDT
We’ve worked incredibly hard to build TTP into the best test prep experience possible, and it would mean a lot to us to win Newsweek’s 2026 Readers’ Choice Award for Best Test Prep. If TTP has helped you, we’d be incredibly grateful for your vote.
Sep 0201:00 PM EDT
-11:59 PM EDT
Take 30% off all study plans with code COURSEWORK - Expires on Monday 9/7
Sep 0410:00 AM PDT
-11:00 AM PDT
What does test anxiety really look like on the GMAT? For many test takers, it does not look like a panic attack. Instead, it shows up as brain fog, rereading, negative comparisons, mental noise....
Sep 0609:30 AM EDT
-12:30 PM EST
Top scores are possible when you enroll in a powerful EA course, taught live online + 6 months access to TTP OnDemand video courses included! Perfect class schedule and easy course access for working professionals. Class starts Sundays Sept. 6, 2026.- Sep 07
12:01 AM PDT
-11:59 PM PDT
On the 7th, GMAT Club Tests will be Free! Including all the Quizzes, Questions, and Tests. 12 AM - 11:59 PM PDT - Sep 09
07:00 AM PDT
-10:00 AM PDT
Meet AdComs and explore top Master’s programs - MiM, MiF, MSc, MSBA and more. - Application Fee Waivers - Free 1-Week of GMAT Club Tests: - Master's Application Toolkit - Grand Prize Giveaway 
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 2108:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
06 Aug 2026, 03:48
Kudos
Bookmarks
A tutoring center pays Clara each week for grading practice tests. In a given week, she earns \(p\) dollars for each of the first 24 tests she grades and \(p + 8\) dollars for each test she grades beyond the first 24. If Clara graded 27 tests last week, what is the value of \(p\)?
(1) Clara earned \(3p + 24\) dollars for the tests she graded beyond the first 24.
(2) If Clara had graded 35 tests last week instead of 27 tests, she would have earned \(8p + 64\) dollars more.
(1) Clara earned \(3p + 24\) dollars for the tests she graded beyond the first 24.
(2) If Clara had graded 35 tests last week instead of 27 tests, she would have earned \(8p + 64\) dollars more.
06 Aug 2026, 03:48
Kudos
Bookmarks
Official Solution:
A tutoring center pays Clara each week for grading practice tests. In a given week, she earns \(p\) dollars for each of the first 24 tests she grades and \(p + 8\) dollars for each test she grades beyond the first 24. If Clara graded 27 tests last week, what is the value of \(p\)?
(1) Clara earned \(3p + 24\) dollars for the tests she graded beyond the first 24.
Since Clara graded 3 tests beyond the first 24, her pay for those tests was:
\(3(p + 8) = 3p + 24\)
This statement is already implied by the stem and gives no numerical value for \(p\).
Not sufficient.
(2) If Clara had graded 35 tests last week instead of 27 tests, she would have earned \(8p + 64\) dollars more.
Going from 27 tests to 35 tests adds 8 tests. Since all of those additional tests are beyond the first 24, each would be paid at \(p + 8\) dollars.
So the additional pay would be:
\(8(p + 8) = 8p + 64\)
This statement is also already implied by the stem and gives no numerical value for \(p\).
Not sufficient.
(1)+(2) Both statements only restate information already implied by the payment rule. No actual dollar amount is given, so \(p\) cannot be determined.
Not sufficient.
Answer: E
A tutoring center pays Clara each week for grading practice tests. In a given week, she earns \(p\) dollars for each of the first 24 tests she grades and \(p + 8\) dollars for each test she grades beyond the first 24. If Clara graded 27 tests last week, what is the value of \(p\)?
(1) Clara earned \(3p + 24\) dollars for the tests she graded beyond the first 24.
Since Clara graded 3 tests beyond the first 24, her pay for those tests was:
\(3(p + 8) = 3p + 24\)
This statement is already implied by the stem and gives no numerical value for \(p\).
Not sufficient.
(2) If Clara had graded 35 tests last week instead of 27 tests, she would have earned \(8p + 64\) dollars more.
Going from 27 tests to 35 tests adds 8 tests. Since all of those additional tests are beyond the first 24, each would be paid at \(p + 8\) dollars.
So the additional pay would be:
\(8(p + 8) = 8p + 64\)
This statement is also already implied by the stem and gives no numerical value for \(p\).
Not sufficient.
(1)+(2) Both statements only restate information already implied by the payment rule. No actual dollar amount is given, so \(p\) cannot be determined.
Not sufficient.
Answer: E
