Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Aug 2710:00 AM EDT
-11:00 AM EDT
We’ve worked incredibly hard to build TTP into the best test prep experience possible, and it would mean a lot to us to win Newsweek’s 2026 Readers’ Choice Award for Best Test Prep. If TTP has helped you, we’d be incredibly grateful for your vote.
Sep 0201:00 PM EDT
-11:59 PM EDT
Take 30% off all study plans with code COURSEWORK - Expires on Monday 9/7
Sep 0410:00 AM PDT
-11:00 AM PDT
What does test anxiety really look like on the GMAT? For many test takers, it does not look like a panic attack. Instead, it shows up as brain fog, rereading, negative comparisons, mental noise....
Sep 0609:30 AM EDT
-12:30 PM EST
Top scores are possible when you enroll in a powerful EA course, taught live online + 6 months access to TTP OnDemand video courses included! Perfect class schedule and easy course access for working professionals. Class starts Sundays Sept. 6, 2026.- Sep 07
12:01 AM PDT
-11:59 PM PDT
On the 7th, GMAT Club Tests will be Free! Including all the Quizzes, Questions, and Tests. 12 AM - 11:59 PM PDT - Sep 09
07:00 AM PDT
-10:00 AM PDT
Meet AdComs and explore top Master’s programs - MiM, MiF, MSc, MSBA and more. - Application Fee Waivers - Free 1-Week of GMAT Club Tests: - Master's Application Toolkit - Grand Prize Giveaway 
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 2108:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
06 Aug 2026, 04:02
Kudos
Bookmarks
At a music audition, judges assigned scores to 9 applicants. Among the applicants, 3 tied for the lowest score of 14 points, and 2 tied for the highest score of 65 points. If the median score of the 9 applicants was 50 points, what was the average (arithmetic mean) score of the 9 applicants?
(1) If the applicants who received 14 points or 65 points are not considered, the median score of the remaining applicants is 56 points.
(2) If the applicants who received 14 points or 65 points are not considered, the range of the remaining scores is 12 points.
(1) If the applicants who received 14 points or 65 points are not considered, the median score of the remaining applicants is 56 points.
(2) If the applicants who received 14 points or 65 points are not considered, the range of the remaining scores is 12 points.
06 Aug 2026, 04:02
Kudos
Bookmarks
Official Solution:
At a music audition, judges assigned scores to 9 applicants. Among the applicants, 3 tied for the lowest score of 14 points, and 2 tied for the highest score of 65 points. If the median score of the 9 applicants was 50 points, what was the average (arithmetic mean) score of the 9 applicants?
Since exactly 3 applicants scored the lowest score of 14, exactly 2 applicants scored the highest score of 65, and the median score was 50, the scores, arranged in ascending order, can be written as:
\(14, 14, 14, a, 50, b, c, 65, 65\)
The question asks for the average score, so we need the value of \(a + b + c\).
(1) If the applicants who received 14 points or 65 points are not considered, the median score of the remaining applicants is 56 points.
After removing the three 14s and the two 65s, the remaining scores are:
\(a, 50, b, c\)
The median of these 4 scores is 56, so:
\(\frac{50 + b}{2} = 56\)
\(50 + b = 112\)
\(b = 62\)
But \(a\) and \(c\) are still not fixed.
Not sufficient.
(2) If the applicants who received 14 points or 65 points are not considered, the range of the remaining scores is 12 points.
After removing the three 14s and the two 65s, the remaining scores are:
\(a, 50, b, c\)
The range is 12, so:
\(c - a = 12\)
But this does not determine \(a + b + c\).
Not sufficient.
(1)+(2) From statement (1):
\(b = 62\)
So the remaining scores are:
\(a, 50, 62, c\)
From statement (2), the range of these numbers, \(c - a\), is 12.
Since the difference between 50 and 62 is already 12, and \(a \leq 50 < 62 \leq c\), we must have:
\(a = 50\) and \(c = 62\)
Thus, the 9 scores are:
\(14, 14, 14, 50, 50, 62, 62, 65, 65\)
The average can be found.
Sufficient.
Answer: C
At a music audition, judges assigned scores to 9 applicants. Among the applicants, 3 tied for the lowest score of 14 points, and 2 tied for the highest score of 65 points. If the median score of the 9 applicants was 50 points, what was the average (arithmetic mean) score of the 9 applicants?
Since exactly 3 applicants scored the lowest score of 14, exactly 2 applicants scored the highest score of 65, and the median score was 50, the scores, arranged in ascending order, can be written as:
\(14, 14, 14, a, 50, b, c, 65, 65\)
The question asks for the average score, so we need the value of \(a + b + c\).
(1) If the applicants who received 14 points or 65 points are not considered, the median score of the remaining applicants is 56 points.
After removing the three 14s and the two 65s, the remaining scores are:
\(a, 50, b, c\)
The median of these 4 scores is 56, so:
\(\frac{50 + b}{2} = 56\)
\(50 + b = 112\)
\(b = 62\)
But \(a\) and \(c\) are still not fixed.
Not sufficient.
(2) If the applicants who received 14 points or 65 points are not considered, the range of the remaining scores is 12 points.
After removing the three 14s and the two 65s, the remaining scores are:
\(a, 50, b, c\)
The range is 12, so:
\(c - a = 12\)
But this does not determine \(a + b + c\).
Not sufficient.
(1)+(2) From statement (1):
\(b = 62\)
So the remaining scores are:
\(a, 50, 62, c\)
From statement (2), the range of these numbers, \(c - a\), is 12.
Since the difference between 50 and 62 is already 12, and \(a \leq 50 < 62 \leq c\), we must have:
\(a = 50\) and \(c = 62\)
Thus, the 9 scores are:
\(14, 14, 14, 50, 50, 62, 62, 65, 65\)
The average can be found.
Sufficient.
Answer: C
