Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 0201:00 PM EDT
-11:59 PM EDT
Take 30% off all study plans with code COURSEWORK - Expires on Monday 9/7
Sep 0410:00 AM PDT
-11:00 AM PDT
What does test anxiety really look like on the GMAT? For many test takers, it does not look like a panic attack. Instead, it shows up as brain fog, rereading, negative comparisons, mental noise....
Sep 0609:30 AM EDT
-12:30 PM EST
Top scores are possible when you enroll in a powerful EA course, taught live online + 6 months access to TTP OnDemand video courses included! Perfect class schedule and easy course access for working professionals. Class starts Sundays Sept. 6, 2026.- Sep 07
12:01 AM PDT
-11:59 PM PDT
On the 7th, GMAT Club Tests will be Free! Including all the Quizzes, Questions, and Tests. 12 AM - 11:59 PM PDT - Sep 09
07:00 AM PDT
-10:00 AM PDT
Meet AdComs and explore top Master’s programs - MiM, MiF, MSc, MSBA and more. - Application Fee Waivers - Free 1-Week of GMAT Club Tests: - Master's Application Toolkit - Grand Prize Giveaway 
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 2108:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
06 Aug 2026, 05:32
Kudos
Bookmarks
At a school fundraiser, a snack table sold four types of items: fruit cups, granola bars, sandwich boxes, and salad bowls. A fruit cup cost $3, a granola bar cost $5, a sandwich box cost $9, and a salad bowl cost $14. If the snack table sold 21 items in total, at least one of each type, and collected $180, how many granola bars were sold?
(1) The number of granola bars sold was equal to the number of sandwich boxes sold.
(2) The snack table sold 4 fruit cups and 5 sandwich boxes.
(1) The number of granola bars sold was equal to the number of sandwich boxes sold.
(2) The snack table sold 4 fruit cups and 5 sandwich boxes.
06 Aug 2026, 05:32
Kudos
Bookmarks
Official Solution:
At a school fundraiser, a snack table sold four types of items: fruit cups, granola bars, sandwich boxes, and salad bowls. A fruit cup cost $3, a granola bar cost $5, a sandwich box cost $9, and a salad bowl cost $14. If the snack table sold 21 items in total, at least one of each type, and collected $180, how many granola bars were sold?
Let \(F\), \(G\), \(S\), and \(L\) be the numbers of fruit cups, granola bars, sandwich boxes, and salad bowls sold, respectively.
Given:
\(F + G + S + L = 21\) (i)
\(3F + 5G + 9S + 14L = 180\) (ii)
The question asks for \(G\).
(1) The number of granola bars sold was equal to the number of sandwich boxes sold.
So \(G = S\).
Then from (i):
\(F + 2G + L = 21\)
and from (ii):
\(3F + 14G + 14L = 180\)
Multiply the first equation by 3:
\(3F + 6G + 3L = 63\)
Subtract from \(3F + 14G + 14L = 180\):
\(8G + 11L = 117\)
Now since \(G\) and \(L\) must be positive integers, we should check whether this equation gives one or more than one set of solutions for \((G, L)\):
\(11L = 117 - 8G\)
So, \(117 - 8G\) must be a positive multiple of 11: \(110, 99, 88, 77, \ldots, 11\). Only \(G = 5\) and \(L = 7\) work. So \(G = 5\).
Sufficient.
(2) The snack table sold 4 fruit cups and 5 sandwich boxes.
So \(F = 4\) and \(S = 5\).
From the total number of items:
\(4 + G + 5 + L = 21\)
\(G + L = 12\)
From the total revenue:
\(3 * 4 + 5G + 9 * 5 + 14L = 180\)
\(12 + 5G + 45 + 14L = 180\)
\(5G + 14L = 123\)
So, we have two distinct linear equations with two unknowns: \(G + L = 12\) and \(5G + 14L = 123\). We can solve and get the value of \(G\).
Sufficient.
Answer: D
At a school fundraiser, a snack table sold four types of items: fruit cups, granola bars, sandwich boxes, and salad bowls. A fruit cup cost $3, a granola bar cost $5, a sandwich box cost $9, and a salad bowl cost $14. If the snack table sold 21 items in total, at least one of each type, and collected $180, how many granola bars were sold?
Let \(F\), \(G\), \(S\), and \(L\) be the numbers of fruit cups, granola bars, sandwich boxes, and salad bowls sold, respectively.
Given:
\(F + G + S + L = 21\) (i)
\(3F + 5G + 9S + 14L = 180\) (ii)
The question asks for \(G\).
(1) The number of granola bars sold was equal to the number of sandwich boxes sold.
So \(G = S\).
Then from (i):
\(F + 2G + L = 21\)
and from (ii):
\(3F + 14G + 14L = 180\)
Multiply the first equation by 3:
\(3F + 6G + 3L = 63\)
Subtract from \(3F + 14G + 14L = 180\):
\(8G + 11L = 117\)
Now since \(G\) and \(L\) must be positive integers, we should check whether this equation gives one or more than one set of solutions for \((G, L)\):
\(11L = 117 - 8G\)
So, \(117 - 8G\) must be a positive multiple of 11: \(110, 99, 88, 77, \ldots, 11\). Only \(G = 5\) and \(L = 7\) work. So \(G = 5\).
Sufficient.
(2) The snack table sold 4 fruit cups and 5 sandwich boxes.
So \(F = 4\) and \(S = 5\).
From the total number of items:
\(4 + G + 5 + L = 21\)
\(G + L = 12\)
From the total revenue:
\(3 * 4 + 5G + 9 * 5 + 14L = 180\)
\(12 + 5G + 45 + 14L = 180\)
\(5G + 14L = 123\)
So, we have two distinct linear equations with two unknowns: \(G + L = 12\) and \(5G + 14L = 123\). We can solve and get the value of \(G\).
Sufficient.
Answer: D
