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06 Aug 2026, 05:34
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An electronics retailer ships Model X TV sets in shipping units. Each shipping unit consists of one TV set and its protective packaging. Before July 1, the protective packaging weighed 25% of the TV set’s weight. If, on July 1, the retailer begins shipping a newer version of the Model X TV set with revised protective packaging, by what percent will the shipping weight of each unit change on July 1?
(1) On July 1, the weight of the TV set will increase by 20%.
(2) On July 1, the revised protective packaging will weigh 50% of the newer version of the TV set’s weight.
(1) On July 1, the weight of the TV set will increase by 20%.
(2) On July 1, the revised protective packaging will weigh 50% of the newer version of the TV set’s weight.
06 Aug 2026, 05:34
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Official Solution:
An electronics retailer ships Model X TV sets in shipping units. Each shipping unit consists of one TV set and its protective packaging. Before July 1, the protective packaging weighed 25% of the TV set’s weight. If, on July 1, the retailer begins shipping a newer version of the Model X TV set with revised protective packaging, by what percent will the shipping weight of each unit change on July 1?
Let \(T\) be the weight of the TV set before July 1. Before July 1, the protective packaging weighed \(25\%\) of the TV set’s weight, so the original shipping weight of each unit was:
\(T + 0.25T = 1.25T\)
The question asks for the percent change in the shipping weight of each unit.
(1) On July 1, the weight of the TV set will increase by \(20\%\).
So the newer version of the TV set will weigh \(1.2T\).
But we do not know the weight of the revised protective packaging. So the new shipping weight cannot be determined.
Not sufficient.
(2) On July 1, the revised protective packaging will weigh \(50\%\) of the newer version of the TV set’s weight.
This tells us the packaging weight relative to the newer TV set’s weight, but it does not tell us the newer TV set’s weight. So the new shipping weight cannot be determined.
Not sufficient.
(1)+(2) From statement (1), the newer version of the TV set weighs \(1.2T\).
From statement (2), the revised protective packaging weighs \(50\%\) of the newer TV set’s weight, so:
\(0.50 * 1.2T = 0.6T\)
So the new shipping weight is:
\(1.2T + 0.6T = 1.8T\)
The original shipping weight was \(1.25T\).
So the percent increase is:
\(\frac{1.8T - 1.25T}{1.25T} * 100 =\)
\(= \frac{0.55}{1.25} * 100 =\)
\(= 44\%\)
Sufficient.
Answer: C
An electronics retailer ships Model X TV sets in shipping units. Each shipping unit consists of one TV set and its protective packaging. Before July 1, the protective packaging weighed 25% of the TV set’s weight. If, on July 1, the retailer begins shipping a newer version of the Model X TV set with revised protective packaging, by what percent will the shipping weight of each unit change on July 1?
Let \(T\) be the weight of the TV set before July 1. Before July 1, the protective packaging weighed \(25\%\) of the TV set’s weight, so the original shipping weight of each unit was:
\(T + 0.25T = 1.25T\)
The question asks for the percent change in the shipping weight of each unit.
(1) On July 1, the weight of the TV set will increase by \(20\%\).
So the newer version of the TV set will weigh \(1.2T\).
But we do not know the weight of the revised protective packaging. So the new shipping weight cannot be determined.
Not sufficient.
(2) On July 1, the revised protective packaging will weigh \(50\%\) of the newer version of the TV set’s weight.
This tells us the packaging weight relative to the newer TV set’s weight, but it does not tell us the newer TV set’s weight. So the new shipping weight cannot be determined.
Not sufficient.
(1)+(2) From statement (1), the newer version of the TV set weighs \(1.2T\).
From statement (2), the revised protective packaging weighs \(50\%\) of the newer TV set’s weight, so:
\(0.50 * 1.2T = 0.6T\)
So the new shipping weight is:
\(1.2T + 0.6T = 1.8T\)
The original shipping weight was \(1.25T\).
So the percent increase is:
\(\frac{1.8T - 1.25T}{1.25T} * 100 =\)
\(= \frac{0.55}{1.25} * 100 =\)
\(= 44\%\)
Sufficient.
Answer: C
