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18 Jun 2018, 05:33
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E
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Difficulty:
15%
(low)
Question Stats:
96% (00:39) correct
4%
(01:43)
wrong
based on 25
sessions
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The probability that event A occurs is \(\frac{1}{3}\), and the probability that event B occurs is \(\frac{1}{12}\). If events A and B are independent, what is the probability that both events A and B occur?
A. \(\frac{1}{6}\)
B. \(\frac{1}{12}\)
C. \(\frac{1}{15}\)
D. \(\frac{1}{18}\)
E. \(\frac{1}{36}\)
A. \(\frac{1}{6}\)
B. \(\frac{1}{12}\)
C. \(\frac{1}{15}\)
D. \(\frac{1}{18}\)
E. \(\frac{1}{36}\)
18 Jun 2018, 05:33
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Official Solution:
The probability that event A occurs is \(\frac{1}{3}\), and the probability that event B occurs is \(\frac{1}{12}\). If events A and B are independent, what is the probability that both events A and B occur?
A. \(\frac{1}{6}\)
B. \(\frac{1}{12}\)
C. \(\frac{1}{15}\)
D. \(\frac{1}{18}\)
E. \(\frac{1}{36}\)
If events A and B are independent, then \(P(A∩B) = P(A)P(B). So, P(A∩B) = P(A)P(B) = (\frac{1}{3})*(\frac{1}{12}) = \frac{1}{36}\).
Answer: E
The probability that event A occurs is \(\frac{1}{3}\), and the probability that event B occurs is \(\frac{1}{12}\). If events A and B are independent, what is the probability that both events A and B occur?
A. \(\frac{1}{6}\)
B. \(\frac{1}{12}\)
C. \(\frac{1}{15}\)
D. \(\frac{1}{18}\)
E. \(\frac{1}{36}\)
If events A and B are independent, then \(P(A∩B) = P(A)P(B). So, P(A∩B) = P(A)P(B) = (\frac{1}{3})*(\frac{1}{12}) = \frac{1}{36}\).
Answer: E
13 Apr 2024, 06:51
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