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Find the combined rate of (A+B)
R*T=w
R*4.5=\(\frac{3}{4}\)
R=\(\frac{1}{6}\) work per hour

Find the rate of Machine A
R*T=W
R*6=\(\frac{1}{4}\)
R=\(\frac{1}{24} \)work per hour

Now to get the individual rate of B, subtract A's rate per hour from the combined rate per hour
\(\frac{1}{6}\) - \(\frac{1}{24}\) =\( \frac{1}{8 }\) work per hour

Find the time machine A take process the entire work.
R*T=W
\(\frac{1}{8}\) * T= 1
T= 8
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Working simultaneously it took machine A and B 4.5hrs to finish 3/4 of work.

Combined rate = Work/Time
3/4 ÷ 9/2= 1/6
A finishes 1/4 of work in 6 hours
Rate of A = 1/4÷6 = 1/24
Rate of B=combined rate -rate of A.
1/6-1/24 = 1/8
It takes B 8 hours to finish entire work.
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