|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
19 May 2025, 00:30
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
86% (01:22) correct
14%
(01:33)
wrong
based on 58
sessions
History
Date
Time
Result
Not Attempted Yet
Machine J runs at a constant rate and produces a lot consisting of 300 bottles in 4 hours. How much less time would it take to produce the lot of bottles if both machines J and P were run simultaneously?
(1) Machine J can only produce a maximum of 10 lots per day.
(2) Machine J produces twice the number of bottles per hour as machine P.
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
(1) Machine J can only produce a maximum of 10 lots per day.
(2) Machine J produces twice the number of bottles per hour as machine P.
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
19 May 2025, 02:21
Kudos
Bookmarks
How much less time machines J and P take to produce 300 bottles together compared to J alone.
J produces 300 bottles in 4 hours (rate: \(\frac{300}{4} = 75\) bottles/hour). Need time for J+P together.
Statement 2 gives P’s rate relative to J, allowing J+P time calculation. S1 adds no relevant info for P.
Answer: B
J produces 300 bottles in 4 hours (rate: \(\frac{300}{4} = 75\) bottles/hour). Need time for J+P together.
| Source | Information | Sufficiency |
| Stem | J: 300 bottles in 4 hours | Insufficient, no P rate |
| Statement 1 | J: max 10 lots/day | Insufficient, no P rate |
| Statement 2 | J rate: 2x P rate | Sufficient, J+P rate calculable |
| Statements 1 + 2 | DON'T CHECK ! S2 ENOUGH !!! |
Statement 2 gives P’s rate relative to J, allowing J+P time calculation. S1 adds no relevant info for P.
Answer: B
19 May 2025, 04:08
Kudos
Bookmarks
Rate of J = 300/4
Bottles in a lot = 300
We need time taken to produce the lot of bottles if both machines J and P were run simultaneously?
S1
J can produce max of 10 lots
No info on P
Insufficient
Interestingly note, if J produces 1 lot in 4hrs, then in a day max 24/4 = 6 lots can be produced logically but this is not a concern.
S2
Machine J produces twice the number of bottles per hour as machine P.
This means in 4ours P can produce only 150 bottles
Together they produced 300+150 bottles in 4hrs = 450
Time to produce 300 bottles together = 4*300/450 = 8/3 hrs
Diff in time = 4-8/3
Sufficient
Answer b
Bottles in a lot = 300
We need time taken to produce the lot of bottles if both machines J and P were run simultaneously?
S1
J can produce max of 10 lots
No info on P
Insufficient
Interestingly note, if J produces 1 lot in 4hrs, then in a day max 24/4 = 6 lots can be produced logically but this is not a concern.
S2
Machine J produces twice the number of bottles per hour as machine P.
This means in 4ours P can produce only 150 bottles
Together they produced 300+150 bottles in 4hrs = 450
Time to produce 300 bottles together = 4*300/450 = 8/3 hrs
Diff in time = 4-8/3
Sufficient
Answer b
Bunuel
