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Math Expert
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Mark and Kate individually take 12 hours more and 27 hours more, respe
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26 Sep 2018, 05:17
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61% (02:33) correct 39% (02:53) wrong based on 126 sessions
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Mark and Kate individually take 12 hours more and 27 hours more, respectively, to complete a certain project than what they would have taken to complete the same project working together. How many hours do Mark and Kate take to complete the project, working together? (A) 12 (B) 16 (C) 18 (D) 24 (E) 39
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Re: Mark and Kate individually take 12 hours more and 27 hours more, respe
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27 Sep 2018, 04:30
Bunuel wrote: Mark and Kate individually take 12 hours more and 27 hours more, respectively, to complete a certain project than what they would have taken to complete the same project working together. How many hours do Mark and Kate take to complete the project, working together?
(A) 12 (B) 16 (C) 18 (D) 24 (E) 39 Say they both take T hrs when working together. When Mark works independently, he takes 12 hrs to do what Kate does in T hrs. Ratio of speed of Mark:Kate = T:12 When Kate works independently, she takes 27 hrs to do what Mark does in T hrs. Ratio of speed of Mark:Kate = 27:T \(\frac{T}{12} = \frac{27}{T}\) \(T = 18 hrs\)
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Re: Mark and Kate individually take 12 hours more and 27 hours more, respe
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26 Sep 2018, 21:02
Bunuel wrote: Mark and Kate individually take 12 hours more and 27 hours more, respectively, to complete a certain project than what they would have taken to complete the same project working together. How many hours do Mark and Kate take to complete the project, working together?
(A) 12 (B) 16 (C) 18 (D) 24 (E) 39 The statement becomes \(\frac{1}{x+12}\)+\(\frac{1}{x+27}\)=\(\frac{1}{x}\) Substitute the choices and see what fits in... (A) 12.....1/24+1/27=1/12.....no because 1/12 is 2 times 1/24 (B) 16.....1/28+1/41=1/16.....no,because 41 cannot get cancelled being prime (C) 18......1/30+1/45=1/15....75/30*45=5/2*45=1/2*9=1/18..yes (D) 24......1/36+1/51=1/24...again no (E) 39..same way no C
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Re: Mark and Kate individually take 12 hours more and 27 hours more, respe
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26 Sep 2018, 21:45
*(1/x+12)+(1/x+27)= 1/x *(x+27+x+12)/[(x+12)(x+27)]=1/x *(2x+39)/[(x+12)(x+27)]=1/x 2x^2+39x=x^2+39x+324 *X^2324=0 *X=18
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Re: Mark and Kate individually take 12 hours more and 27 hours more, respe
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27 Sep 2018, 04:13
Can someone explain the equation set up?



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Mark and Kate individually take 12 hours more and 27 hours more, respe
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27 Sep 2018, 13:30
chetan2u wrote: Bunuel wrote: Mark and Kate individually take 12 hours more and 27 hours more, respectively, to complete a certain project than what they would have taken to complete the same project working together. How many hours do Mark and Kate take to complete the project, working together?
(A) 12 (B) 16 (C) 18 (D) 24 (E) 39 The statement becomes \(\frac{1}{x+12}\)+\(\frac{1}{x+27}\)=\(\frac{1}{x}\) Substitute the choices and see what fits in... (A) 12.....1/24+1/27=1/12.....no because 1/12 is 2 times 1/24 (B) 16.....1/28+1/41=1/16.....no,because 41 cannot get cancelled being prime (C) 18......1/30+1/45=1/15....75/30*45=5/2*45=1/2*9=1/18..yes (D) 24......1/36+1/51=1/24...again no (E) 39..same way no C chetan2u why are you adding values in denominator, as per the question if they work together with +12 and+27 hours it, then working together it means that their times should be x12 and x27 respectively



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Re: Mark and Kate individually take 12 hours more and 27 hours more, respe
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29 Sep 2018, 18:02
Bunuel wrote: Mark and Kate individually take 12 hours more and 27 hours more, respectively, to complete a certain project than what they would have taken to complete the same project working together. How many hours do Mark and Kate take to complete the project, working together?
(A) 12 (B) 16 (C) 18 (D) 24 (E) 39 We can let x = the number of hours it would take Mark and Kate to finish the project if they were working together. Thus, Mark’s rate by himself is (x + 12) hours, and Kate’s rate by herself is (x + 27) hours. Let’s create the equation for their rates. Mark’s rate is 1/(x + 12), Kate’s rate is 1/(x + 27), and their combined rate is 1/x. Thus, we have: 1/(x+12) + 1/(x+27) = 1/x Multiplying by x(x+27)(x+12) we have: x(x+27) + x(x+12) = (x+27)(x+12) x^2 + 27x + x^2 + 12x = x^2 + 39x + 324 x^2 = 324 x = 18 Answer: C
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Re: Mark and Kate individually take 12 hours more and 27 hours more, respe
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08 Oct 2018, 03:24
Mark and Kate individually take 12 hours more and 27 hours more, respectively, to complete a certain project than what they would have taken to complete the same project working together. How many hours do Mark and Kate take to complete the project, working together?
x = √(a*b)
x = time taken for Mark and Kate to do job together, a = the additional time Mark takes to complete the job alone (i.e T+12), b = the additional time Kate takes to complete job alone (i.e T +27)
x = √324 x = 18
This is the fastest way for these.
Got this method from ganand.



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Re: Mark and Kate individually take 12 hours more and 27 hours more, respe
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25 Nov 2018, 02:55
VeritasKarishma wrote: Bunuel wrote: Mark and Kate individually take 12 hours more and 27 hours more, respectively, to complete a certain project than what they would have taken to complete the same project working together. How many hours do Mark and Kate take to complete the project, working together?
(A) 12 (B) 16 (C) 18 (D) 24 (E) 39 Say they both take T hrs when working together. When Mark works independently, he takes 12 hrs to do what Kate does in T hrs. Ratio of speed of Mark:Kate = T:12 When Kate works independently, she takes 27 hrs to do what Mark does in T hrs. Ratio of speed of Mark:Kate = 27:T \(\frac{T}{12} = \frac{27}{T}\) \(T = 18 hrs\) Can you please explain this?




Re: Mark and Kate individually take 12 hours more and 27 hours more, respe
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25 Nov 2018, 02:55






