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# Martha biked 18 2/3 miles in 2 hours and 40 minutes. What was her aver

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Math Expert
Joined: 02 Sep 2009
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Martha biked 18 2/3 miles in 2 hours and 40 minutes. What was her aver  [#permalink]

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02 Aug 2018, 00:16
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Difficulty:

15% (low)

Question Stats:

78% (01:10) correct 22% (01:37) wrong based on 77 sessions

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Martha biked $$18 \frac{2}{3}$$ miles in 2 hours and 40 minutes. What was her average rate of speed in miles per hour?

A. 7

B. $$7 \frac{2}{3}$$

C. $$8 \frac{1}{3}$$

D. 9

E. $$9 \frac{1}{3}$$

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Re: Martha biked 18 2/3 miles in 2 hours and 40 minutes. What was her aver  [#permalink]

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02 Aug 2018, 00:33
Ans: A
Miles = 56/3 miles Time taken: 2 +2/3 hrs = 8/3 hrs
Velocity = Miles/Time = 7 miles/hrs

Bunuel wrote:
Martha biked $$18 \frac{2}{3}$$ miles in 2 hours and 40 minutes. What was her average rate of speed in miles per hour?

A. 7

B. $$7 \frac{2}{3}$$

C. $$8 \frac{1}{3}$$

D. 9

E. $$9 \frac{1}{3}$$

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Re: Martha biked 18 2/3 miles in 2 hours and 40 minutes. What was her aver  [#permalink]

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02 Aug 2018, 03:11
Bunuel wrote:
Martha biked $$18 \frac{2}{3}$$ miles in 2 hours and 40 minutes. What was her average rate of speed in miles per hour?

Distance = $$18 \frac{2}{3}$$ = 56 / 3 miles
Time = 2 hours + 40 minutes = 2 hrs + 2 / 3 hrs = 8 / 3 hrs

Speed = Distance / Time = 56/3 / 8/3 = 7 miles per hour

Hence, A.
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Martha biked 18 2/3 miles in 2 hours and 40 minutes. What was her aver  [#permalink]

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03 Aug 2018, 12:20
$$18 \frac{2}{3} = \frac{56}{3}$$
2 hours and 40 minutes equals to 160 minutes
Lets say that R is the average rate

$$\frac{56}{3R} = \frac{160}{60}$$
$$\frac{56}{3R} = \frac{8}{3}$$
$$\frac{56}{R} = 8$$
Cross multiplication:
$$56 = R*8$$
$$R = \frac{56}{8}$$
$$R = 7$$

Option A
Martha biked 18 2/3 miles in 2 hours and 40 minutes. What was her aver &nbs [#permalink] 03 Aug 2018, 12:20
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