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17 Nov 2011, 16:39
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
(N/A)
Question Stats:
71% (01:08) correct
29%
(00:35)
wrong
based on 12
sessions
History
Date
Time
Result
Not Attempted Yet
What is the minimum percentage increase in the mean of set X {-4, -1, 0, 6, 9} if its two smallest elements are replaced with two different primes?
(A) 25%
(B) 50%
(C) 75%
(D) 100%
(E) 200%
OA is not provided. But I got D. Is D the right answer?
(A) 25%
(B) 50%
(C) 75%
(D) 100%
(E) 200%
OA is not provided. But I got D. Is D the right answer?
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17 Nov 2011, 17:29
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I do also. The given set comes to an average of 2 and the smallest *different* primes you can substitute would be 2 and 3. That would bring the new average to 4. Of course, 4 is 200% of 2, but it's just a 100% increase.
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18 Nov 2011, 01:37
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I go with D....
1st average is 2
2nd average is 4
percentage increase:
4-2/2*100= 2/2*100=1*100=100%
hope that helps
1st average is 2
2nd average is 4
percentage increase:
4-2/2*100= 2/2*100=1*100=100%
hope that helps
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
