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# Median problem

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Senior Manager
Joined: 08 Jan 2009
Posts: 317

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10 Feb 2009, 19:09
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Can you please explain the problem?

Table :
Ann \$450,000
Bob \$360,000
cal \$190,000
Dot \$210,000
Ed \$680,000

the table shows the total sales in july for the 5 sales people at Acme truck sales.It was dicovered that one of Cal's sales was incorrectly recorded as one of Ann's sales. After the error was corrected ,Ann total sales were still higher than cal's total sales and the median of the 5 sales was 330,000.What was the value of the incorrectly recorded sale?

a) \$30,000
b) \$48,000
c) \$90,000
d) \$120,000
e) \$140,000
SVP
Joined: 29 Aug 2007
Posts: 2453

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10 Feb 2009, 22:36
tkarthi4u wrote:
Can you please explain the problem?

Table :
Ann \$450,000
Bob \$360,000
cal \$190,000
Dot \$210,000
Ed \$680,000

the table shows the total sales in july for the 5 sales people at Acme truck sales.It was dicovered that one of Cal's sales was incorrectly recorded as one of Ann's sales. After the error was corrected ,Ann total sales were still higher than cal's total sales and the median of the 5 sales was 330,000.What was the value of the incorrectly recorded sale?

a) \$30,000
b) \$48,000
c) \$90,000
d) \$120,000
e) \$140,000

D: The question is looks not clearly typed. What I sense is D. 120,000.
Since median is 330,000 after the correction, only way that 330,000 is median possible is to reduce Ann's sales is to be reduced by 120,000.

Hence Cal's sales is 190,000 + 120,000 = 310,000.
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GT

SVP
Joined: 07 Nov 2007
Posts: 1761
Location: New York

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10 Feb 2009, 23:07
GMAT TIGER wrote:
tkarthi4u wrote:
Can you please explain the problem?

Table :
Ann \$450,000
Bob \$360,000
cal \$190,000
Dot \$210,000
Ed \$680,000

the table shows the total sales in july for the 5 sales people at Acme truck sales.It was dicovered that one of Cal's sales was incorrectly recorded as one of Ann's sales. After the error was corrected ,Ann total sales were still higher than cal's total sales and the median of the 5 sales was 330,000.What was the value of the incorrectly recorded sale?

a) \$30,000
b) \$48,000
c) \$90,000
d) \$120,000
e) \$140,000

D: The question is looks not clearly typed. What I sense is D. 120,000.
Since median is 330,000 after the correction, only way that 330,000 is median possible is to reduce Ann's sales is to be reduced by 120,000.

Hence Cal's sales is 190,000 + 120,000 = 310,000.

agree with GT..
median values must be Ann's sale.
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VP
Joined: 18 May 2008
Posts: 1203

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11 Feb 2009, 10:27
Let x be the corrected figure. Since median is 3,30,000. This must be Ann's corrected sale. Thus 450,000=330,000+x
Hence, x=120,000
Re: Median problem   [#permalink] 11 Feb 2009, 10:27
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# Median problem

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