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MGMAT problem

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Intern
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Joined: 11 Sep 2009
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MGMAT problem [#permalink]

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New post 22 Sep 2009, 19:09
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A
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Sam earned a $2000 , commission on a big sale , raising his average commission by $100.If Sam's new average commission is $900, how many sales has he made?

Ans:
a) 11
b) 12
c) 13

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Manager
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Re: MGMAT problem [#permalink]

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New post 22 Sep 2009, 19:24
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I think 12 sales (including the last one).

X represents the average prior to the last sale and N - the number of sales (NOT including the last sale)
x+100=900
x=800
sum of commissions fron N sales=800N

the average of total sales (oncluding the last one)= \(\frac{800N+2000}{N+1}=900\)
from here, N=11 and N+1=12

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Senior Manager
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Re: MGMAT problem [#permalink]

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New post 22 Sep 2009, 22:51
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Arrived at the same conclusion, slightly diff working but same thing.

Previous Average
1) Sum/N = 800

New Average
2) (Sum+2000) / (N+1) = 900

Subtract equations:
2)-1)
X+2000 = 900N+900
X = 800N
2000 = 100N+900
100N = 1100
N = 11

Answer: A

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Manager
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Joined: 15 Sep 2009
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Re: MGMAT problem [#permalink]

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New post 23 Sep 2009, 00:36
I wud go with option 12


800*x + 2000 = 900(x+1)
100x = 1100
x = 11
x+1 = 12

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Senior Manager
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Joined: 31 Aug 2009
Posts: 415

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Location: Sydney, Australia
Re: MGMAT problem [#permalink]

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New post 23 Sep 2009, 01:03
Sorry, you are correct. Classic case of not reading question stem it is 12 not 11.

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Intern
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Re: MGMAT problem [#permalink]

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New post 23 Sep 2009, 06:09
Yes , 12 is the right answer .

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Manager
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Re: MGMAT problem [#permalink]

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New post 23 Sep 2009, 10:26
Soln:
New average is 900 for x + 1 items
Earlier average is 800 for x items

eq is
2000 + 800x = 900(x + 1)
solving for x
x = 11

Since the new total is (x + 1) therefore we have total of 12 items sold

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Re: MGMAT problem [#permalink]

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New post 21 Nov 2017, 09:31
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Re: MGMAT problem   [#permalink] 21 Nov 2017, 09:31
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