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26 Jul 2008, 01:44
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Is x > y?
(1) SQRT(X)> y
(2) x^3 > y
How to solve it ? There is explaination on mgmat , but I cannot understand.
Thanks,
(1) SQRT(X)> y
(2) x^3 > y
How to solve it ? There is explaination on mgmat , but I cannot understand.
Thanks,
Archived Topic
Hi there,
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26 Jul 2008, 09:09
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1) 2 > 1 also 4 > 1
5 > 3 also 25 > 1
0 > -1
This statement will always hold true. So question can be answer hence answer should be A or D.
2) x^3 > y.
(4)^3 > 5 but 4 < 5 (counter case for statement 2)
(5)^3 > 4 also 5 > 4 (supporting statement 2)
Thereby Maybe case so on basis of B question cannot be answered.
So answer is A.
5 > 3 also 25 > 1
0 > -1
This statement will always hold true. So question can be answer hence answer should be A or D.
2) x^3 > y.
(4)^3 > 5 but 4 < 5 (counter case for statement 2)
(5)^3 > 4 also 5 > 4 (supporting statement 2)
Thereby Maybe case so on basis of B question cannot be answered.
So answer is A.
26 Jul 2008, 09:19
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i think its C.
all you know from 1 is that x > y^2, i.e. that x is a positive number. we can have x=1/2 and y=1/2, but y^2=1/4 and so even though x=y, x >y^2 ... so this statement alone cant be sufficient.
all you know from 1 is that x > y^2, i.e. that x is a positive number. we can have x=1/2 and y=1/2, but y^2=1/4 and so even though x=y, x >y^2 ... so this statement alone cant be sufficient.
