Abhishek009 I seldom use Nova's prep, but when I do I'll make sure to post some problems

As for my solution:

We are given the time and the speed at which Fritz runs so we can simply use the \(Distance = Rate*Time\) formula to find the solution,

\(D1= \frac{1}{3}t * 10mph\) \(D2= \frac{2}{3}t * 5mph\), \(D1= \frac{10}{3}t\), \(D2= \frac{10}{3}t\),

and since we also know the distance (30 miles) we can simply calculate

\(30 = \frac{10}{3}t + \frac{10}{3}t\) \(= \frac{20}{3}t\) -> \(\frac{20}{3}t = 30\) -> \(t = \frac{90}{20}\)

-> \(t = 4,5h\)

D)