Mukesh, Manish, Lalu and Jaggi bought a MOKIA mobile for £60. Mukesh

Question

Mukesh, Manish, Lalu and Jaggi bought a MOKIA mobile for £60. Mukesh paid one–half of the sum of the amounts paid by the other persons. Manish paid one–third of the sum of the amounts paid by the other persons. Lalu paid one–fourth of the sum of the amounts paid by the other persons. How much did Jaggi have to pay?

(A) £ 13
(B) £ 15
(C) £ 17
(D) £ 23
(E) None of these

(A) £ 13
(B) £ 15
(C) £ 17
(D) £ 23
(E) None of these

GMATWhizTeam · Answer

Solution   :
We are given,
 • Mukesh, Manish, Lalu and Jaggi bought a MOKIA mobile.
• Total amount paid for the mobile =  £60  
We need to find the amount paid by Jaggi.

When Mukesh paid one–half of the sum of the amounts paid by the other persons  
Let the sum of amounts paid by others =  x 
Then, amount paid by Mukesh =  \frac{1}{2} * x 
We know, 
The total amount paid by all = 60
Mukesh + others = 60
⟹  \frac{1}{2} * x  +  x  = 60
⟹  \frac{x}{2}  +  x  = 60
⟹  \frac{3x}{2}  = 60
⟹ x =  \frac{60 * 2}{3} 
⟹ x = 40 
Therefore,  amount paid by Mukesh  =  \frac{1}{2} * 40  =  £20

When Manish paid one–third of the sum of the amounts paid by the other persons  
Let the sum of amounts paid by others =  y 
Then, amount paid by Manish =  \frac{1}{3} * y 
We know, 
The total amount paid by all = 60
Manish + others = 60
⟹  \frac{1}{3} * y  +  y  = 60
⟹  \frac{y}{3}  +  y  = 60
⟹  \frac{4y}{3}  = 60
⟹ y =  \frac{60 * 3}{4} 
⟹ y = 45 
Therefore,  amount paid by Manish  =  \frac{1}{3} * 45  =  £15

When Lalu paid one–fourth of the sum of the amounts paid by the other persons  
Let the sum of amounts paid by others =  z 
Then, amount paid by Lalu =  \frac{1}{4} * z 
We know, 
The total amount paid by all = 60
Lalu + others = 60
⟹  \frac{1}{4} * z  +  z  = 60
⟹  \frac{z}{4}  +  z  = 60
⟹  \frac{5z}{4}  = 60
⟹ z =  \frac{60 * 4}{5} 
⟹ z = 48
Therefore,  amount paid by Manish  =  \frac{1}{4} * 48  =  £12

Thus, the  amount paid by Jaggi  = 60 - 20 - 15 - 12 =  13

Hence, the correct answer is   Option A  .

MathRevolution · Answer

Mukesh(Mu), Manish(Ma), Lalu(L), and Jaggi(J)

=> Mu + Ma + L + J = £60

Mukesh paid one–half of the sum of the amounts paid by the other persons:  Mu =\frac{ Ma + L + J }{ 2}

=> 2(Mu) = Ma + L+ J

=> Mu + 2(Mu) = £60

=> 3Mu = £60

=> Mu = £20

=> Ma + L + J = £60 - £20 = £40 or L + J = £40 - Ma

Manish paid one–third of the sum of the amounts paid by the other persons: 3(Ma) = 20 + L + J

=> 3Ma = £20 + £40 - Ma

=> 4Ma = £60

=> Ma = £15

=> L + J = £60 - £20 - £15 = £25

Lalu paid one–fourth of the sum of the amounts paid by the other persons: 4(L) = Mu + Ma + J

=> 4L - J = 35

Adding both equations, we get 5L = 60 or L = 12

Therefore, J = 25 - 12 = 13

Answer A

kevincan · Answer

Muk paid 1/3 of total cost £20
Man paid 1/4 of total cost £15
Lalu paid 1/5 of total cost £ 12
They paid a total of £47
Jaggi paid the remaining £13

Mukesh, Manish, Lalu and Jaggi bought a MOKIA mobile for £60. Mukesh

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Mukesh, Manish, Lalu and Jaggi bought a MOKIA mobile for £60. Mukesh

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