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09 Oct 2003, 20:25
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N from 1-100 inclusive
How many #'s such tha n*(n+1) divided by 4.
25 mutliples of 4
25 numbers before 4 ( 3,4 ; 7,8 ; 11,12 ; 15,16 ...... 99,100)
24 numbers after 4 ( 4,5 ; 8,9 ; 12,13 ; 16,17 .........96,97)
So, a total of 74.
Is that correct?
thanks
praetorian
How many #'s such tha n*(n+1) divided by 4.
25 mutliples of 4
25 numbers before 4 ( 3,4 ; 7,8 ; 11,12 ; 15,16 ...... 99,100)
24 numbers after 4 ( 4,5 ; 8,9 ; 12,13 ; 16,17 .........96,97)
So, a total of 74.
Is that correct?
thanks
praetorian
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10 Oct 2003, 05:10
Kudos
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is my solution above correct?
thanks
praetorian
thanks
praetorian
10 Oct 2003, 06:02
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praetorian123
N from 1-100 inclusive
How many #'s such tha n*(n+1) divided by 4.
25 mutliples of 4
25 numbers before 4 ( 3,4 ; 7,8 ; 11,12 ; 15,16 ...... 99,100)
24 numbers after 4 ( 4,5 ; 8,9 ; 12,13 ; 16,17 .........96,97)
So, a total of 74.
Is that correct?
thanks
praetorian
How many #'s such tha n*(n+1) divided by 4.
25 mutliples of 4
25 numbers before 4 ( 3,4 ; 7,8 ; 11,12 ; 15,16 ...... 99,100)
24 numbers after 4 ( 4,5 ; 8,9 ; 12,13 ; 16,17 .........96,97)
So, a total of 74.
Is that correct?
thanks
praetorian
You can't take the original multiples of 4 in account because you're asked for n * (n+1). And don't forget the last number 10100. That makes the total of 50 numbers.
