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I have a question about the notation of ratios. I do understand the math behind it yet sometimes it seems to me that questions use the notation interchangeably. Here are two examples of what I mean:
1. Example If a=2b, 1/2b=c and 4c=3d what is the ratio of d to a?
I thought it's 3/1 but the correct answer is 1/3.
2. Example Given that a is the average (arithmetic mean) of the first nine positive multiples of six and b is the median of the first twelve positive multiples of six, what is the ratio of a to b?
Following the first example I answered 13:10 yet here the correct answer is 10:13.
My question: Can someone please explain the logic behind this and give a rule how to chose the right ratio.
Thanks already in advance!
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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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I have a question about the notation of ratios. I do understand the math behind it yet sometimes it seems to me that questions use the notation interchangeably. Here are two examples of what I mean:
1. Example If a=2b, 1/2b=c and 4c=3d what is the ratio of d to a?
I thought it's 3/1 but the correct answer is 1/3.
2. Example Given that a is the average (arithmetic mean) of the first nine positive multiples of six and b is the median of the first twelve positive multiples of six, what is the ratio of a to b?
Following the first example I answered 13:10 yet here the correct answer is 10:13.
My question: Can someone please explain the logic behind this and give a rule how to chose the right ratio.
Thanks already in advance!
Show more
Quote:
If a = 2b, 1/2*b = c, and 4c = 3d, then what is the ratio of d to a?
Given that a is the average (arithmetic mean) of the first nine positive multiples of six and b is the median of the first twelve positive multiples of six, what is the ratio of a to b?
A. 3:4 B. 10:13 C. 5:6 D. 13:10 E. 4:3
Show more
The first nine positive multiples of six are {6, 12, 18, 24, 30, 36, 42, 48, 54} The first twelve positive multiples of six are {6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72}
Both sets are evenly spaced, thus their median=mean: a=30 and b=(36+42)/2=39 --> a/b=30/39=10/13.
I have a question about the notation of ratios. I do understand the math behind it yet sometimes it seems to me that questions use the notation interchangeably. Here are two examples of what I mean:
1. Example If a=2b, 1/2b=c and 4c=3d what is the ratio of d to a?
I thought it's 3/1 but the correct answer is 1/3.
2. Example Given that a is the average (arithmetic mean) of the first nine positive multiples of six and b is the median of the first twelve positive multiples of six, what is the ratio of a to b?
Following the first example I answered 13:10 yet here the correct answer is 10:13.
My question: Can someone please explain the logic behind this and give a rule how to chose the right ratio.
I have a question about the notation of ratios. I do understand the math behind it yet sometimes it seems to me that questions use the notation interchangeably. Here are two examples of what I mean:
1. Example If a=2b, 1/2b=c and 4c=3d what is the ratio of d to a?
I thought it's 3/1 but the correct answer is 1/3.
2. Example Given that a is the average (arithmetic mean) of the first nine positive multiples of six and b is the median of the first twelve positive multiples of six, what is the ratio of a to b?
Following the first example I answered 13:10 yet here the correct answer is 10:13.
My question: Can someone please explain the logic behind this and give a rule how to chose the right ratio.
I have a question about the notation of ratios. I do understand the math behind it yet sometimes it seems to me that questions use the notation interchangeably. Here are two examples of what I mean:
1. Example If a=2b, 1/2b=c and 4c=3d what is the ratio of d to a?
I thought it's 3/1 but the correct answer is 1/3.
Show more
Rephrase "what is the ratio of d to a" algebraically to "d/a=?"
To get a numerical answer for your ratio, you will need the variables to cancel out. Put d in terms of c and a in terms of c (a->b->c) d=(4/3)c, a=2b=4c. ((4/3)c)/4c = (4/3)/4 = 1/3
Quote:
2. Example Given that a is the average (arithmetic mean) of the first nine positive multiples of six and b is the median of the first twelve positive multiples of six, what is the ratio of a to b?
Show more
Same thing. If you rephrase "what is the ratio of a to b" into algebra, you get "a/b=?"
The average of numbers that are evenly spaced apart is the median. The median of the first nine positive multiples of 6 is 30. Median of the first 12 positive multiples of 6 is the mean of the 6th and 7th positive multiples of 6, so (36+42)/2= 39
I have a question about the notation of ratios. I do understand the math behind it yet sometimes it seems to me that questions use the notation interchangeably. Here are two examples of what I mean:
1. Example If a=2b, 1/2b=c and 4c=3d what is the ratio of d to a?
I thought it's 3/1 but the correct answer is 1/3.
2. Example Given that a is the average (arithmetic mean) of the first nine positive multiples of six and b is the median of the first twelve positive multiples of six, what is the ratio of a to b?
Following the first example I answered 13:10 yet here the correct answer is 10:13.
My question: Can someone please explain the logic behind this and give a rule how to chose the right ratio.
Thanks already in advance!
Show more
If you're unsure about which order to write a ratio in, think about it in terms of actual numbers.
When the problem says "what is the ratio of a to b," you would write the value of a first, then the value of b.
If it says "what is the ratio of d to a," you would write the value of d first, then the value of a.
So, for instance, look at your first problem. One set of numbers that works is a = 2, b = 1, c = 1/2, and d = 2/3.
The ratio of D to A is 2/3 to 2, because D could equal 2/3 and A could equal 2.
Then, simplify that ratio by multiplying by 3:
D to A = 2 to 6
Then, divide by 2:
D to A = 1 to 3
That's how you know it's 1 to 3 and not 3 to 1.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.