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# Number System

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Intern
Joined: 23 Sep 2018
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23 Sep 2018, 19:25
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Why is 123! Is in the form of 4n?

Why is 35! Divisible by 10?

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Retired Moderator
Joined: 27 Oct 2017
Posts: 1229
Location: India
GPA: 3.64
WE: Business Development (Energy and Utilities)

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23 Sep 2018, 20:05
N! = 1*2*3*4*...N
( Note that n! is defined for positive integers only)
Hence, 123! = 1*2*3*4*5*...123
Hence, it is in form of 4n.
Similarly, 35! = 1*2*3*4*5*...*35.
Hence it is divisible by 10.
Tag me, in case of any doubt.

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Joined: 23 Sep 2018
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24 Sep 2018, 05:29
Can you explain it how? gmatbusters

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Retired Moderator
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Location: India
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24 Sep 2018, 05:33
In mathematics, the factorial of a non-negative integer n, denoted by n!, is the product of all positive integers less than or equal to n. For example,

5! = 5*4*3*2*1

The value of 0! is 1, according to the convention for an empty product.
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Posts: 1229
Location: India
GPA: 3.64
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24 Sep 2018, 05:53
Refer this link for the number system theory
https://gmatclub.com/forum/math-number-theory-88376.html
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Math Expert
Joined: 02 Sep 2009
Posts: 56244

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05 Oct 2018, 05:39
PBORA1011 wrote:
Why is 123! Is in the form of 4n?

Why is 35! Divisible by 10?

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TOPIC IS LOCKED AND ARCHIVED.
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Re: Number System   [#permalink] 05 Oct 2018, 05:39
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