Last visit was: 29 Apr 2026, 23:54 It is currently 29 Apr 2026, 23:54
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
User avatar
rdw28
User avatar
Joined: 12 May 2006
Last visit: 17 Jul 2007
Posts: 78
Own Kudos:
2
Location: Philadelphia
Posts: 78
Kudos: 2
OA will be provided later.. 31 Jul 2006, 23:23
Kudos
Add Kudos
Bookmarks
Bookmark this Post
OA will be provided later...



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
User avatar
jaynayak
User avatar
Joined: 30 Mar 2006
Last visit: 07 Jul 2008
Posts: 893
Own Kudos:
648
Posts: 893
Kudos: 648
OA will be provided later.. 31 Jul 2006, 23:31
Kudos
Add Kudos
Bookmarks
Bookmark this Post
3 addtional machines will be required.

I use the following theorem .

When one quantity increases(decreases) while the other increases(decreases), set ratios equal.
When one increases(decreases), while the other decreases(increases), set products equal.

In the case number of machines increase while number of days decreases, hence we will set the products equal.
Let x be the number of machines that will finish the work in 8 days.

6*12 = x*8
x = 9

hence 9 machines are required to finish the work in 8 days.
No of additonal machines = 9-6 = 3
avatar
amit_gupta21
avatar
Joined: 06 Jun 2006
Last visit: 22 Mar 2011
Posts: 5
Posts: 5
Kudos: 0
OA will be provided later.. 31 Jul 2006, 23:37
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Ans should be B ie. 3 more machines
User avatar
hemamalinidr
User avatar
Joined: 12 Jun 2006
Last visit: 11 Mar 2017
Posts: 26
Own Kudos:
2
Location: Hyderabad, India
Posts: 26
Kudos: 2
OA will be provided later.. 31 Jul 2006, 23:57
Kudos
Add Kudos
Bookmarks
Bookmark this Post
m1*t1 = m2*t2

6*12 = m2*8

m2 = 9

12-9 = 3 more machines
User avatar
rdw28
User avatar
Joined: 12 May 2006
Last visit: 17 Jul 2007
Posts: 78
Own Kudos:
2
Location: Philadelphia
Posts: 78
Kudos: 2
OA will be provided later.. 01 Aug 2006, 07:33
Kudos
Add Kudos
Bookmarks
Bookmark this Post
B it is... good job guys.
User avatar
MANRED
User avatar
Joined: 02 May 2006
Last visit: 03 Nov 2006
Posts: 19
Own Kudos:
1
Posts: 19
Kudos: 1
OA will be provided later.. 01 Aug 2006, 07:45
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I did this way....

W=RT
W=1 job
T=time
R=work/ time
W=1=R *(6*12) where 12 is the time T and 6 is the number of machines, because we need the relation (job per machine per day)
So we have that R=1/6*12
Then, to have the work done is 8 days:
W=1=(1/6*12)*X*8

Then, 6*12=X*8
X=9

We need then 3 machines



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!