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11 Mar 2020, 03:58
Kudos
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
95% (00:55) correct
5%
(00:49)
wrong
based on 139
sessions
History
Date
Time
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Not Attempted Yet
Of 30 integers, 15 are in set A, 22 are in set B, and 8 are in both set A and B. How many of the integers are in NEITHER set A nor set B ?
A. 0
B. 1
C. 2
D. 3
E. 4
A. 0
B. 1
C. 2
D. 3
E. 4
Archit3110
Major Poster
11 Mar 2020, 08:59
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Bunuel
integers in set A= 15 ; in set B = 22 and overalap ; 8
so we have ; 22-8 ; 14 ; 15-14 ; 1
IMO B
11 Mar 2020, 10:38
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Bunuel
n(A) = 15 ; n(B) = 22 & n (AB) = 8
n (AUB) = n(A) + n(B) - n (AB)
Or, n (AUB) = 15 + 22 - 8
Or, n (AUB) = 29
So, Integers that are in NEITHER set A nor set B is 30 - 29 = 1 , Answer must be (B)
