Hi
Bunuel,
I got the correct answer by chance. I did not get the meaning of the question correctly and I seem to be dissatisfied by the approach I followed.
Can you please point out mistake in my approach and/or suggest a better,more efficient way?
total candidates = 200.
So, A U B U C = 200.
100 = A ; 70= B; 140 = C.
40 = A n B (using n to denote intersection)
30 = B n C
60 = A n C
10 = A n B n C
Using AUBUC = A + B + C - {A n B + B n C + C n A} + A n B n C
I get 200 = 190. So I guess there is a gap of 10 somewhere. So let me go with 10.
Bunuel
praveen27sinha
Of the 200 candidates who were interviewed for a position at a call center, 100 had a two-wheeler, 70 had a credit card and 140 had a mobile phone. 40 of them had both, a two-wheeler and a credit card, 30 had both, a credit card and a mobile phone and 60 had both, a two wheeler and mobile phone and 10 had all three. How many candidates had none of the three?
(1) 0
(2) 20
(3) 10
(4) 18
(5) 05
Merging topics. Please refer to the discussion above.