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Solution



Given
    • In a class, there are 36 students.
      o 10 of them are in chess club
      o 13 are in high bridge.

To find
    • The number of student that are in only one of the two clubs if 20 of the students are not in either club

Approach and Working out
Total students of the class – Students who are not part of any club = Students part of chess club + Students part of High bridge - Students part of both the clubs

    • 36 – 20 = 10 + 13 - Students part of both the clubs
    • 16 = 23 - Students part of both the clubs
    • Students part of both the clubs = 7
So, 16 students were part of clubs. And 7 of them were in both of them.
Hence, 16-7 =9 were part of only1 club.

Thus, option B is the correct answer.

Correct Answer: Option B
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Members in only chess + members in only bridge + members in both + members in neither =36
Members in chess + members in bridge + members in both =20
Let the number of members in both = x
10-x +13-x + x =16
x =7
Members in in only one of the two clubs = Members in only chess + members in only bridge = 3+6 =9
Hence B
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Total - neither = Chess + Bridge - Both

=> 36 - 20 = 10 + 13 - Both

=> Both = 10 + 13 - 16 = 7

Chess - Both = Only chess = 10 - 7 = 3

Bridge - Both = Only bridge = 13 - 7 = 6

Total: 3 + 6 = 9

Answer B
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