Bunuel wrote:

arps wrote:

Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. When is y if the 10 years employees become 60% of the total employees?

Ans 200

Step by step:

\(0.7*800=560\) employees have serviced more than 10 years;

We are told that after \(y\)

of those employees leave the company the # of employees who have serviced more than 10 years (\(560-y\)) become 60% of a new total, which will be \(800-y\), so: \(0.6*(800-y)=(560-y)\) --> \(y=200\).

Hope it's clear.

please tell me when I went wrong... my understanding is bit different on this question.

70% are more than 10 years ..... 30% are 10 and less than 10 years.

70%of 800 = 560

30%of 800 = 240

Now Y are going to retire and these Y come in 70% group, resulting in something ... what is that .. 240 becomes 60% of the total now

Here total has to be the decreased number .... then only 60% possible ...

so 60% of (800-y) = 240 ..... why are we taking 560-y as 60%