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# Of the following, which is the closest approximation of 50.2

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Of the following, which is the closest approximation of 50.2  [#permalink]

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Updated on: 01 Nov 2018, 01:50
1
00:00

Difficulty:

5% (low)

Question Stats:

78% (00:47) correct 22% (00:55) wrong based on 177 sessions

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Of the following, which is the closest approximation of 50.2*0.49/199.8

A. 1/10
B. 1/8
C. 1/4
D. 5/4
E. 25/2

Originally posted by Ankit04041987 on 05 Sep 2012, 06:17.
Last edited by pushpitkc on 01 Nov 2018, 01:50, edited 2 times in total.
Renamed the topic and edited the question.
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Re: Of the following, which is the closest approximation of 50.2  [#permalink]

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05 Sep 2012, 06:29
1
Ankit04041987 wrote:
Of the following, which is the closest approximation of 50.2*0.49/199.8

A. 1/10
B. 1/8
C. 1/4
D. 5/4
E. 1/2

$$\frac{50.2*0.49}{199.8}\approx{\frac{50*0.5}{200}}=\frac{25}{200}=\frac{1}{8}.$$

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Re: Of the following, which is the closest approximation of 50.2  [#permalink]

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24 Oct 2012, 04:26
26 secs it took !! og archer lite on manhattan website rocks !!
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Re: Of the following, which is the closest approximation of 50.2  [#permalink]

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19 Dec 2012, 05:38
$$=\frac{50.2*0.49}{199.8}=\frac{(50)(50)x10^{-2}}{200}=\frac{2500*10^{-2}}{200}=125*10^{-3}=\frac{125}{1000}=\frac{1}{8}$$

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Re: Of the following, which is the closest approximation of 50.2  [#permalink]

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16 Sep 2019, 09:25
Ankit04041987 wrote:
Of the following, which is the closest approximation of 50.2*0.49/199.8

A. 1/10
B. 1/8
C. 1/4
D. 5/4
E. 25/2

Of the following, which is the closest approximation of 50.2*0.49/199.8
$$\frac{50 * .5}{200} = \frac{25}{200} = \frac{1}{8}$$

IMO B
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Re: Of the following, which is the closest approximation of 50.2  [#permalink]

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16 Sep 2019, 10:56
Ankit04041987 wrote:
Of the following, which is the closest approximation of 50.2*0.49/199.8

A. 1/10
B. 1/8
C. 1/4
D. 5/4
E. 25/2

50.2 ~ 50 ; 0.49 ~ 0.50 = 1/2 & 199.8 ~ 200

So, We have $$50*\frac{1}{2}/200 = 25/200 = 1/8$$ , Answer must be (B)
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Re: Of the following, which is the closest approximation of 50.2   [#permalink] 16 Sep 2019, 10:56
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