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Of the following, which is the closest approximation to 32/0.256^(1/2)
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Bunuel
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Of the following, which is the closest approximation to 32/0.256^(1/2) [#permalink] New post  22 May 2020, 05:38
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Of the following, which is the closest approximation to \(\frac{32}{\sqrt{0.256}}=\) ?

A. 20
B. 30
C. 60
D. 200
E. 600


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Of the following, which is the closest approximation to 32/0.256^(1/2) [#permalink] New post  22 May 2020, 05:44
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Bunuel wrote:
Of the following, which is the closest approximation to \(\frac{32}{\sqrt{0.256}}=\) ?

A. 20
B. 30
C. 60
D. 200
E. 600


PS21251


\(\frac{32}{\sqrt{0.256}}= \frac{32}{√(256/1000)} = \frac{32*√1000 }{ √256} = \frac{32(10*√10) }{ 16} = 20√10 ≈ 20*3 = 60\)

ANswer: Option C
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Re: Of the following, which is the closest approximation to 32/0.256^(1/2) [#permalink] New post  22 May 2020, 06:12
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Or you can notice that √0.25 = √(1/4) = 1/2, and √0.256 is therefore very close to 1/2. So 32/√0.256 ~ 32/(1/2) = 64, and C is the answer.
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Re: Of the following, which is the closest approximation to 32/0.256^(1/2) [#permalink] New post  22 May 2020, 07:16
Bunuel wrote:
Of the following, which is the closest approximation to \(\frac{32}{\sqrt{0.256}}=\) ?

A. 20
B. 30
C. 60
D. 200
E. 600


PS21251


\(0.50*0.50 = 0.25\)

\(\frac{32}{\sqrt{0.256}}\)

= \(\frac{32}{0.50}\)

= \(64\)

~ \(60\), Answer must be (C)
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Re: Of the following, which is the closest approximation to 32/0.256^(1/2) [#permalink] New post  27 Jun 2022, 07:47
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Bunuel wrote:
Of the following, which is the closest approximation to \(\frac{32}{\sqrt{0.256}}=\) ?

A. 20
B. 30
C. 60
D. 200
E. 600


PS21251


We can save a lot of time by recognizing 0.256 ≈ 0.25, and that √0.25 = 0.5 (since 0.5² = 0.25)

So, we get: \(\frac{32}{\sqrt{0.256}}≈ \frac{32}{\sqrt{0.25}} ≈ \frac{32}{0.5} ≈ 64\)

Answer: C
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Re: Of the following, which is the closest approximation to 32/0.256^(1/2) [#permalink]
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