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Of the following, which is the greatest?

A. \(\frac{7}{9}\)

B. \(\frac{5}{7}\)

C. \((\frac{7}{9})^2\)

D. \((\frac{5}{7})^3\)

E. \((\frac{7}{9})^3\)

The fractions \(\frac{7}{9}\) and \(\frac{5}{7}\) are both between 0 and 1, so raising either of them to a power makes it smaller.

Thus, the powered options are smaller than their original fractions.

Now compare \(\frac{7}{9}\) and \(\frac{5}{7}\).

Use the common denominator 63:

\(\frac{7}{9} = \frac{49}{63}\)

\(\frac{5}{7} = \frac{45}{63}\)

Since \(\frac{49}{63} > \frac{45}{63}\), we have \(\frac{7}{9} > \frac{5}{7}\).

Therefore, \(\frac{7}{9}\) is the greatest value.

Answer: A.

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Of the following, which is the greatest?

A. \(\frac{7}{9}\)

B. \(\frac{5}{7}\)

C. \((\frac{7}{9})^2\)

D. \((\frac{5}{7})^3\)

E. \((\frac{7}{9})^3\)


A positive fraction less than 1 raised to a power is smaller than the original fraction.

So, \(\frac{7 }{9}\) and \(\frac{5}{7 }\) are both greater than either of them raised to a power in (C), (D), or (E).

Thus, we are down to (A) and (B).

\(\frac{7}{9}\) is \(\frac{2}{9}\) less than \(\frac{9}{9} = 1\).

\(\frac{5}{7}\) is \(\frac{2}{7}\) less than \(\frac{7}{7} = 1\)

Thus, since \(\frac{1}{9} < \frac{1}{7} \), \(\frac{7}{9}\) is closer to 1 than \(\frac{5}{ 7}\).

So, \(\frac{7}{9}\) > \(\frac{5}{7}\).

Correct answer: A
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