kush09 wrote:
Of the four-digit integers greater than 9,000, with the sum of their digits greater than 30, what is the sum of the integers that have two pairs of digits such that digits in one pair are equal to each other and the digits of the other pair are equal to each other but distinct from the other two?
Solution:
four-digit integers greater than 9,000:
9001 to 9999
sum of their digits greater than 30:
Only possible 4 digits are 6,7,8,9
one pair are equal to each other and the digits of the other pair are equal to each other but distinct,
means of 4 digits, 2 different integers have to be selected, that gives us 2 set (9,6) and (8,7)
as total 12 different integers are possible :
9669,9966,9696,6699,6969,6996,8778,8787,8877,7887,,7878,7788
Approximately, answer is 12*9000 = 10800, answer should be greater than 10,800, which is only option E.
Could you please share the solution, how OA is C?
9669,9966,9696,6699,6969,6996,8778,8787,8877,7887,,7878,7788
these are not the desired solutions....
only 9977,9988,9779,9889,9898,9797. are the desired solutions.....
numbers should be greater than 9000 and sum of their digits should be greater than 30
Posted from my mobile device