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Of the three-digit positive integers that have no digits equal to zero, how many have two digits that are equal to each other and the remaining digit different from the other two? A. 24 B. 36 C. 72 D. 144 E. 216
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Answer: E. Here is my answer: we call the number is abc (each has the value from 1 to 9). we have 9 pairs of number that equal: (1,1);(2,2);(3,3);...;(9,9) so we have 9 choices for 2 equal numbers, the remaining number has 8 choices(because it's different from the number of 2 equal numbers, forexample if you chose (1,1) then you can chose the remaining number 2,3,...9: 8 choices).so we have 9.8=72 choices for number Now,the posion for number: we have 2C3 choices for the position of 2 equal numbers and 1 for the remaining number, then the choices is : 2C3.1.72=3.1.72=216. So E is my choice
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