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OG11 Q-232 PS 12 Jun 2008, 23:33
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Hello Guys,

I came across the following ques in OG11 and couldnt solve it.

Q-232 If 1/x - 1/x+1 = 1/x+4 then x could be-

(A) 0
(B) -1
(C) -2
(D) -3
(E) -4

Though I could solve it thru backsolving but I didnt understand the normal method which OG explained. (OA is C)

Can anyone solve it with explanations.

Thanks,
GR :?



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durgesh79
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OG11 Q-232 PS 12 Jun 2008, 23:38
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We can simply solve it

1/x + 1/(1+x) = 1/(x+4)

(1+x-x) / (x^2 + x) = 1 / (x+4)

x+4 = x^2 - x

x^2 = 4

x = +/- 2
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OG11 Q-232 PS 12 Jun 2008, 23:48
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ya the answer should be C

i agree with durgesh79 explanations
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OG11 Q-232 PS 12 Jun 2008, 23:54
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durgesh79
We can simply solve it

1/x + 1/(1+x) = 1/(x+4)

(1+x-x) / (x^2 + x) = 1 / (x+4)

x+4 = x^2 - x

x^2 = 4

x = +/- 2
Show more

couldnt not understand buddy. how did 1/x - 1/x+1 = 1/x+4 become 1/x + 1/(1+x) = 1/(x+4) (minus became +)
didnt get the step below as well :?:
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OG11 Q-232 PS 13 Jun 2008, 00:39
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greatchap
durgesh79
We can simply solve it

1/x + 1/(1+x) = 1/(x+4)

(1+x-x) / (x^2 + x) = 1 / (x+4)

x+4 = x^2 - x

x^2 = 4

x = +/- 2

couldnt not understand buddy. how did 1/x - 1/x+1 = 1/x+4 become 1/x + 1/(1+x) = 1/(x+4) (minus became +)
didnt get the step below as well :?:
Show more

My bad, there was a typo in line 1
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OG11 Q-232 PS 13 Jun 2008, 00:56
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how did this come (1+x-x) / (x^2 + x) = 1 / (x+4)

OK, got it. 1/1+x was multiplies by x/x .
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OG11 Q-232 PS 13 Jun 2008, 16:39
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My approach was POE .

Looking at the answer choices you can eliminate 0 , -1 , -4 right off the bat . Plug in -2 ,-3 and -2 gives us the result.



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