GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 17 Jul 2018, 00:53

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# On a certain transatlantic crossing, 20 percent of a ship's

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 47032
On a certain transatlantic crossing, 20 percent of a ship's [#permalink]

### Show Tags

09 Mar 2014, 15:17
3
26
00:00

Difficulty:

35% (medium)

Question Stats:

75% (02:02) correct 25% (02:16) wrong based on 763 sessions

### HideShow timer Statistics

The Official Guide For GMAT® Quantitative Review, 2ND Edition

On a certain transatlantic crossing, 20 percent of a ship's passengers held round-trip tickets and also took their cars aboard the ship. If 60 percent of the passengers with round-trip tickets did not take their cars aboard the ship, what percent of the ship's passengers held round-trip tickets?

(A) 33 1/3%
(B) 40%
(C) 50%
(D) 60%
(E) 66 2/3%

Problem Solving
Question: 146
Category: Arithmetic Percents
Page: 81
Difficulty: 600

GMAT Club is introducing a new project: The Official Guide For GMAT® Quantitative Review, 2ND Edition - Quantitative Questions Project

Each week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

We'll be glad if you participate in development of this project:
2. Please vote for the best solutions by pressing Kudos button;
3. Please vote for the questions themselves by pressing Kudos button;
4. Please share your views on difficulty level of the questions, so that we have most precise evaluation.

Thank you!

_________________
Math Expert
Joined: 02 Sep 2009
Posts: 47032
Re: On a certain transatlantic crossing, 20 percent of a ship's [#permalink]

### Show Tags

09 Mar 2014, 15:17
1
5
SOLUTION

On a certain transatlantic crossing, 20 percent of a ship's passengers held round-trip tickets and also took their cars aboard the ship. If 60 percent of the passengers with round-trip tickets did not take their cars aboard the ship, what percent of the ship's passengers held round-trip tickets?

(A) 33 1/3%
(B) 40%
(C) 50%
(D) 60%
(E) 66 2/3%

Let the total # of passengers be 100.

Now, 20 passengers held round-trip tickets AND cars.

As 60% of the passengers with round-trip tickets did not take their cars then 40% of the passengers with round-trip tickets did take their cars, so # of passengers with round-trip tickets AND cars is 40% of the passengers with round-trip tickets.

If we take # of the passengers with round trip tickets to be $$x$$ then we'll have $$0.4x=20$$ --> $$x=50$$.

_________________
##### General Discussion
Intern
Affiliations: CA, SAP FICO
Joined: 22 Nov 2012
Posts: 35
Location: India
Concentration: Finance, Sustainability
GMAT 1: 620 Q42 V33
GMAT 2: 720 Q47 V41
GPA: 3.2
WE: Corporate Finance (Energy and Utilities)
Re: On a certain transatlantic crossing, 20 percent of a ship's [#permalink]

### Show Tags

09 Mar 2014, 18:18
Assume total passengers = 100,

So people with round ticket and having cars = 20

These 20 people = 40% of total round ticket holders. So total round ticket holders = 60
% of Round Ticket holders = 60/100 = 60%
SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1837
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)
Re: On a certain transatlantic crossing, 20 percent of a ship's [#permalink]

### Show Tags

09 Mar 2014, 19:59
2

Lets say total passengers = 100

Passengers with round ticket & cars = 20

If 60 percent of the passengers with round-trip tickets did not take their cars aboard the ship which means 40% with round trip tickets took cars

40x/100 = 20

x = 50

Attachments

tik.jpg [ 23.4 KiB | Viewed 7943 times ]

_________________

Kindly press "+1 Kudos" to appreciate

Manager
Joined: 01 May 2013
Posts: 61
Re: On a certain transatlantic crossing, 20 percent of a ship's [#permalink]

### Show Tags

09 Mar 2014, 20:14
2
20% of the passengers were RT passengers with cars aboard. 60% of RT passengers did not bring cars. Thus, 20% of all passengers corresponds to 40% of RT passengers.

r = RT
t = total

2r/5 = t/5

r = 5t/10

= t/2

= 50%

OR 40% = 2(20%). 10% of all passengers are 20% of RT, so 100% of RT are 50% of passengers.
Retired Moderator
Joined: 20 Dec 2013
Posts: 180
Location: United States (NY)
GMAT 1: 640 Q44 V34
GMAT 2: 710 Q48 V40
GMAT 3: 720 Q49 V40
GPA: 3.16
WE: Consulting (Venture Capital)
Re: On a certain transatlantic crossing, 20 percent of a ship's [#permalink]

### Show Tags

09 Mar 2014, 21:09
1
Total Passengers = 100
Both RT and Cars = 20

RT*(1-.6) = 20
RT = 50
RT/Passengers = 50/100

C
_________________
Current Student
Joined: 25 Sep 2012
Posts: 271
Location: India
Concentration: Strategy, Marketing
GMAT 1: 660 Q49 V31
GMAT 2: 680 Q48 V34
Re: On a certain transatlantic crossing, 20 percent of a ship's [#permalink]

### Show Tags

09 Mar 2014, 21:37
As there are only percents involve here and no numbers, we can assume some comfortable numbers.

Total = 100
Passenger with round trip+ cars = 20% of Total = 20
Passenger with round trip+no car = 60% of round trip

Hence,
20 = 100% of round trip - 60% of round trip = 40% of round trip
Therefore,
roundtrip = 50
which is 50% of Total

Difficulty level 650 (It took me complete 2 mins which I think makes this problem lengthy)
Time Taken 2:00
Manager
Joined: 20 Dec 2013
Posts: 249
Location: India
Re: On a certain transatlantic crossing, 20 percent of a ship's [#permalink]

### Show Tags

10 Mar 2014, 00:28
1
Option C.
If 60% of passengers with round-trip do not have cars,40% of passengers with round-trip tickets will have their cars on board.
40% of total=20
=50
Director
Joined: 10 Mar 2013
Posts: 562
Location: Germany
Concentration: Finance, Entrepreneurship
GMAT 1: 580 Q46 V24
GPA: 3.88
WE: Information Technology (Consulting)
On a certain transatlantic crossing, 20 percent of a ship's [#permalink]

### Show Tags

15 Jun 2015, 11:07
1
1
We can solve this problem using Double matrix. Unknown NUmber is here the number of pasengers with round trip tickets - let it be X, then 60% of X = 0,6X
Let the Total be 100, then people with Round Trip Tickets and Cars = 20% of 100 = 20

See the attached screenshot and then solve.

20 + 0,6X = X
X = 50
Attachments

Temp.JPG [ 12.22 KiB | Viewed 5954 times ]

_________________

When you’re up, your friends know who you are. When you’re down, you know who your friends are.

800Score ONLY QUANT CAT1 51, CAT2 50, CAT3 50
GMAT PREP 670
MGMAT CAT 630
KAPLAN CAT 660

Current Student
Joined: 18 Oct 2014
Posts: 880
Location: United States
GMAT 1: 660 Q49 V31
GPA: 3.98
On a certain transatlantic crossing, 20 percent of a ship's [#permalink]

### Show Tags

05 Jun 2016, 13:59
pepo wrote:
On a certain boat, 20 % of the passengers have round-trip tickets and are trasporting cars. if 60% of the passengers who have round-trip tickets are not transporting cars, what percent of all the passengers have round-trip ticketsOn a certain boat, 20 % of the passengers have round-trip tickets and are trasporting cars. if 60% of the passengers who have round-trip tickets are not transporting cars, what percent of all the passengers have round-trip tickets?

A 40%
B 50%
C 60%
D 70%
E 80%

Let's suppose total customers are 100 and customers who have round-trip tickets are r

if 60% of the passengers who have round-trip tickets are not transporting cars or 40% who have round trips are transporting cars.

i.e. .6r are not transporting cars and .4r are transporting cars.

Its given that 20 % of the passengers have round-trip tickets and are transporting cars (20 out of 100)

.4r=20
r=50%

_________________

I welcome critical analysis of my post!! That will help me reach 700+

Intern
Joined: 23 Apr 2016
Posts: 22
Location: Finland
GPA: 3.65
Re: On a certain transatlantic crossing, 20 percent of a ship's [#permalink]

### Show Tags

10 Aug 2016, 12:37
1
I have a slight difficulty in understanding the question:
1.On a certain transatlantic crossing, 20 percent of a ship's passengers held round-trip tickets and also took their cars aboard the ship.
2.If 60 percent of the passengers with round-trip tickets did not take their cars aboard the ship, what percent of the ship's passengers held round-trip tickets?

>> So 2nd statement means that 40% have Round trip ticket and also took car.

But in the first sentence it said that percentage of such people who have round trip ticket and brought their cars is 20% ?

How did you guys understand this question ?
Director
Joined: 09 Mar 2016
Posts: 651
On a certain transatlantic crossing, 20 percent of a ship's [#permalink]

### Show Tags

04 Apr 2018, 04:55
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

On a certain transatlantic crossing, 20 percent of a ship's passengers held round-trip tickets and also took their cars aboard the ship. If 60 percent of the passengers with round-trip tickets did not take their cars aboard the ship, what percent of the ship's passengers held round-trip tickets?

(A) 33 1/3%
(B) 40%
(C) 50%
(D) 60%
(E) 66 2/3%

Problem Solving
Question: 146
Category: Arithmetic Percents
Page: 81
Difficulty: 600

GMAT Club is introducing a new project: The Official Guide For GMAT® Quantitative Review, 2ND Edition - Quantitative Questions Project

Each week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

We'll be glad if you participate in development of this project:
2. Please vote for the best solutions by pressing Kudos button;
3. Please vote for the questions themselves by pressing Kudos button;
4. Please share your views on difficulty level of the questions, so that we have most precise evaluation.

Thank you!

generis, pushpitkc,

do you guys have any tips for overlapping sets ? i need some methodologic approach to solve these type of questions

i dont understand whats wrong with my solution

the only thing I would change in my diagram x-20 into 20-x
Attachments

overlapping sets .jpg [ 103.46 KiB | Viewed 1069 times ]

BSchool Forum Moderator
Joined: 26 Feb 2016
Posts: 2933
Location: India
GPA: 3.12
On a certain transatlantic crossing, 20 percent of a ship's [#permalink]

### Show Tags

04 Apr 2018, 06:55
1
dave13 wrote:
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

On a certain transatlantic crossing, 20 percent of a ship's passengers held round-trip tickets and also took their cars aboard the ship. If 60 percent of the passengers with round-trip tickets did not take their cars aboard the ship, what percent of the ship's passengers held round-trip tickets?

(A) 33 1/3%
(B) 40%
(C) 50%
(D) 60%
(E) 66 2/3%

Problem Solving
Question: 146
Category: Arithmetic Percents
Page: 81
Difficulty: 600

GMAT Club is introducing a new project: The Official Guide For GMAT® Quantitative Review, 2ND Edition - Quantitative Questions Project

Each week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

We'll be glad if you participate in development of this project:
2. Please vote for the best solutions by pressing Kudos button;
3. Please vote for the questions themselves by pressing Kudos button;
4. Please share your views on difficulty level of the questions, so that we have most precise evaluation.

Thank you!

generis, pushpitkc,

do you guys have any tips for overlapping sets ? i need some methodologic approach to solve these type of questions

i dont understand whats wrong with my solution

the only thing I would change in my diagram x-20 into 20-x

Hi dave13

Let the ship's passengers who hold round-trip tickets be x
P(Hold round-trip tickets) = x

We are told that 60% of this number did not take their cars
P(Only hold round-trip tickets) = 0.6x
Also, P(Both) = 20%.

If total number of people is 100, P(Both) = 20
P(Hold round-trip ticket) = P(Only hold round-trip tickets) + P(Both)

$$x = 0.6x + 20$$ -> $$x - 0.6x = 20$$ -> $$0.4x = 20$$ -> $$x = \frac{20}{0.4} = 50$$
Therefore, the percentage of ship's passengers who hold round trip tickets is $$\frac{50}{100} = 50$$% (Option C)

Hope this helps you.
_________________

You've got what it takes, but it will take everything you've got

Director
Joined: 09 Mar 2016
Posts: 651
Re: On a certain transatlantic crossing, 20 percent of a ship's [#permalink]

### Show Tags

04 Apr 2018, 12:29
pushpitkc wrote:
dave13 wrote:
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

On a certain transatlantic crossing, 20 percent of a ship's passengers held round-trip tickets and also took their cars aboard the ship. If 60 percent of the passengers with round-trip tickets did not take their cars aboard the ship, what percent of the ship's passengers held round-trip tickets?

(A) 33 1/3%
(B) 40%
(C) 50%
(D) 60%
(E) 66 2/3%

Problem Solving
Question: 146
Category: Arithmetic Percents
Page: 81
Difficulty: 600

GMAT Club is introducing a new project: The Official Guide For GMAT® Quantitative Review, 2ND Edition - Quantitative Questions Project

Each week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

We'll be glad if you participate in development of this project:
2. Please vote for the best solutions by pressing Kudos button;
3. Please vote for the questions themselves by pressing Kudos button;
4. Please share your views on difficulty level of the questions, so that we have most precise evaluation.

Thank you!

generis, pushpitkc,

do you guys have any tips for overlapping sets ? i need some methodologic approach to solve these type of questions

i dont understand whats wrong with my solution

the only thing I would change in my diagram x-20 into 20-x

Hi dave13

Let the ship's passengers who hold round-trip tickets be x
P(Hold round-trip tickets) = x

We are told that 60% of this number did not take their cars
P(Only hold round-trip tickets) = 0.6x
Also, P(Both) = 20%.

If total number of people is 100, P(Both) = 20
P(Hold round-trip ticket) = P(Only hold round-trip tickets) + P(Both)

$$x = 0.6x + 20$$ -> $$x - 0.6x = 20$$ -> $$0.4x = 20$$ -> $$x = \frac{20}{0.4} = 50$$
Therefore, the percentage of ship's passengers who hold round trip tickets is $$\frac{50}{100} = 50$$% (Option C)

Hope this helps you.

hi pushpitkc, thanks!

here $$x = 0.6x + 20$$ why do you denote 20 as number and not percent ? 60 and 20 are both percentages ?

do you mind correcting my diagram so as i can see visually what i did wrong ?
BSchool Forum Moderator
Joined: 26 Feb 2016
Posts: 2933
Location: India
GPA: 3.12
Re: On a certain transatlantic crossing, 20 percent of a ship's [#permalink]

### Show Tags

04 Apr 2018, 23:35
1
dave13 wrote:

hi pushpitkc, thanks!

here $$x = 0.6x + 20$$ why do you denote 20 as number and not percent ? 60 and 20 are both percentages ?

do you mind correcting my diagram so as i can see visually what i did wrong ?

Hey dave13

Attachment:

Diagram.png [ 4.61 KiB | Viewed 919 times ]

Here, we are assuming the total number of passengers to be 100.
However, we have no clarity about the total number of passengers with round-trip tickets(which we are assuming to be x)

60% of the passengers who hold round-trip tickets do not take their cars.
Therefore, the total number of passengers who only have round-trip tickets are 60% of x or $$\frac{60}{100}*x = 0.6x$$

In the diagram, it is clear why P(Hold round-trip ticket) = P(Only hold round-trip tickets) + P(Both)

So, we arrive at the equation x=0.6x+20

Hope that it's clear now!
_________________

You've got what it takes, but it will take everything you've got

Target Test Prep Representative
Affiliations: Target Test Prep
Joined: 04 Mar 2011
Posts: 2669
Re: On a certain transatlantic crossing, 20 percent of a ship's [#permalink]

### Show Tags

06 Apr 2018, 08:46
1
Bunuel wrote:

On a certain transatlantic crossing, 20 percent of a ship's passengers held round-trip tickets and also took their cars aboard the ship. If 60 percent of the passengers with round-trip tickets did not take their cars aboard the ship, what percent of the ship's passengers held round-trip tickets?

(A) 33 1/3%
(B) 40%
(C) 50%
(D) 60%
(E) 66 2/3%

We can let the number of passengers = 100.

Thus, 20 passengers held round trip tickets and took their cars aboard the ship. Since we are given that 60 percent of the passengers with round-trip tickets did not take their cars aboard the ship, the 20 passengers who held round trip tickets and took their cars aboard the ship represent 40 percent of the passengers with round-trip tickets. If n = the number of passengers with round-trip tickets, we have:

20 = 0.4n

n = 20/0.4 = 200/4 = 50

Thus, 50/100 = 50% of the ship’s passengers held round-trip tickets.

_________________

Jeffery Miller

GMAT Quant Self-Study Course
500+ lessons 3000+ practice problems 800+ HD solutions

Re: On a certain transatlantic crossing, 20 percent of a ship's   [#permalink] 06 Apr 2018, 08:46
Display posts from previous: Sort by

# Events & Promotions

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.