kevincan
On a cruise, 60% of the passengers were adults and 40% were children. The adults consisted of men and women. On the return cruise, the number of men decreased by 20%, the number of women decreased by 10%, and the number of children increased by 50%. The total number of passengers increased by 9.5%. On the first cruise, what percent of the adults were men?
A. 45%
B. 60%
C. 70%
D. 75%
E. 80%
Let the total population be 100.
60%(100) = 60 are adults = men + women.
40%(100) = 40 are children.
100 = m + (60-m) + 40 The population increased by 9.5% = 109.5
The men decreased by 20% = 0.2 , and the value becomes 0.8m
The women decreased by 10% = 0.1, and the value becomes 0.1*(60-m)
The children population increased by 50% = 20
So, the value
9.5 = -0.2m - 0.1(60-m) +20 Solving, we get
9.5 = 14 - 0.1m
m = (4.5/0.1)
m = 45
Fraction of adults who are men = 45/60 = (3/4) =
75% Option D