Bunuel
On a z day outdoor adventure expedition, 4 children consumed food costing x dollars and supplies costing t dollars. For the same food and supply costs per child per day, what would be the total cost of food and supplies consumed by 8 children during a 10 day outdoor adventure?
A. 20(x + t)/z
B. (5x + 5t)/z
C. 32(x + t)/z
D. 20z/(x + t)
E. 20(x + z)/t
Two ways, we could do the algebra or we could plug in. I'm usually a big fan of plugging in, but with three variables, that can get pretty clunky, so if you're comfortable with the algebra, that might be a better option. Here are both.
AlgebraFor z days and 4 children, we spend x+t dollars.
For z days and 8 children, we would spend 2(x+t).
For 10 days and 8 children, we would spend (10/z)*2(x+t), which is 20(x+t)/z.
Answer choice A.
Plugging InWe have variables in the question that are repeated in the answer choices. Let's just plug in.
We can see that we're being asked about a 10-day adventure. Let's use z=5.
On a 5-day trip, 4 kids consume x=$20 of food and t=$25 of supplies for a total of $45.
If we double the kids, we'd have a 5-day trip and 8 kids for $90.
Then double the days and we have a 10-day trip and 8 kids for $180.
Let's plug z=5, x=20, and t=45 into the answer choices and find one that equals 180.
A. 20(45)/5 = 4(45) = 180
B. (100+125)/5 = 225/5 Wrong.
C. 32(45)/25 Wrong.
D. 100/45 Wrong.
E. 20(25)/25 = 20 Wrong.
Answer choice A.