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1) find the circumference for both wheels

Wheel 1 on Saturday = 2(25)pi = 50pi
Wheel 2 on Sunday = 2(30)pi = 60 pi

2) lets add in a distance of our liking, lets say 300pi so that both circumferences divide well into it

3) divide 1) 300pi by 50pi = 6 | 2) divide 300pi by 60pi = 5

4) so ratio of day 1 revolutions to day 2 revolutions is 6:5

therefore if we want to find the revolutions change in day two compared to day one we just do 5/6 = 1/6 less than = decrease of 16.67.
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Alright, picking numbers here could be a good strategy:

Let's say the distance is 150 inches, with 150 LCM of 25 and 3.

Rotation done by the 25 inches weel \( = \frac{150}{25} = 6\)

Rotation done by the 30 inches weel\( = \frac{150}{30} = 5\)

Let's find the percentage difference:

%difference \( = \frac{(6 - 5)}{6} = \frac{1}{6}\) which equals to a 16.67% decrease
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Hello from the GMAT Club BumpBot!

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