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11 Apr 2026, 13:24
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
69% (02:30) correct
31%
(02:48)
wrong
based on 26
sessions
History
Date
Time
Result
Not Attempted Yet
On the first day of the year, Ramon and Marga each had $500 in their savings accounts. From that day on, each saved money at a constant rate. At some point later in the year, Ramon had $564 and Marga had $604. How much money did Ramon have in his account at the time when Marga had $1,124?
(A) 820
(B) 852
(C) 864
(D) 884
(E) 916
(A) 820
(B) 852
(C) 864
(D) 884
(E) 916
11 Apr 2026, 21:40
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Bookmarks
On the first day of the year, Ramon and Marga both had $500. Since each saves money at a constant rate, the amount in each person’s account increases linearly over time.
At some point later in the year:
Ramon has $564, which is an increase of $64 from $500.
Marga has $604, which is an increase of $104 from $500.
Thus, for the same amount of time, Marga saves money faster than Ramon, and the ratio of their savings rates is 64/104 = 8/13.
Now consider the time at which Marga has $1,124. This is an increase of 1,124 − 500 = 624.
Using the same savings-rate ratio, Ramon’s increase at that time is 624 × (8/13) = 384.
Therefore, Ramon’s total amount is 500 + 384 = 884.
Final Answer:
884
At some point later in the year:
Ramon has $564, which is an increase of $64 from $500.
Marga has $604, which is an increase of $104 from $500.
Thus, for the same amount of time, Marga saves money faster than Ramon, and the ratio of their savings rates is 64/104 = 8/13.
Now consider the time at which Marga has $1,124. This is an increase of 1,124 − 500 = 624.
Using the same savings-rate ratio, Ramon’s increase at that time is 624 × (8/13) = 384.
Therefore, Ramon’s total amount is 500 + 384 = 884.
Final Answer:
884
