Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 2008:00 AM PDT
-08:30 AM PDT
What’s in it for you- Live Profile Evaluation Chat Session with Jenifer Turtschanow, CEO, ARINGO. Come with your details prepared and ARINGO will share insights! Pre-MBA Role/Industry, YOE, Exam Score, C/GPA, ECs Post-MBA Role/ Industry & School List.
Jun 1006:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
11 Nov 2023, 08:39
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
89% (00:56) correct
11%
(01:12)
wrong
based on 324
sessions
History
Date
Time
Result
Not Attempted Yet
On the number line shown above, the shaded interval is the graph of which of the following inequalities?
(A) |x| ≤ 4
(B) |x| ≤ 6
(C) |x − 2| ≤ 4
(D) |x − 1| ≤ 5
(E) |x + 2| ≤ 4
Attachment:
Number line.png [ 5 KiB | Viewed 4118 times ]
12 Nov 2023, 07:31
Kudos
Bookmarks
Bunuel
OA is E
Posted from my mobile device
Attachments
Screenshot_20231112_200037_Samsung Notes.jpg [ 193.25 KiB | Viewed 3647 times ]
09 Jun 2025, 19:27
Kudos
Bookmarks
Region given in the line is -6 ≤ x ≤ 2
(A) |x| ≤ 4
This is of the form |x| ≤ A and can be opened as -A ≤ x ≤ A
=> -4 ≤ x ≤ 4
This is partially in the range and partially not, so FALSE
(B) |x| ≤ 6
=> -6 ≤ x ≤ 6
This is partially in the range and partially not, so FALSE
(C) |x − 2| ≤ 4
=> -4 ≤ x - 2 ≤ 4
Adding 2 on all the sides we get
=> -4 + 2 ≤ x - 2 + 2 ≤ 4 + 2
=> -2 ≤ x ≤ 6
This is partially in the range and partially not, so FALSE
(D) |x − 1| ≤ 5
=> -5 ≤ x - 1 ≤ 5
Adding 1 on all the sides we get
=> -5 + 1 ≤ x - 1 + 1 ≤ 5 + 1
=> -4 ≤ x ≤ 6
This is partially in the range and partially not, so FALSE
(E) |x + 2| ≤ 4
=> -4 ≤ x + 2 ≤ 4
Subtracting -2 from all the sides we get
=> -4 - 2 ≤ x + 2 - 2 ≤ 4 - 2
=> -6 ≤ x ≤ 2
=> TRUE
So, Answer will be E
Hope it helps!
Playlist on Solve problems on Absolute Value here
Watch the following video to MASTER Absolute Values
(A) |x| ≤ 4
This is of the form |x| ≤ A and can be opened as -A ≤ x ≤ A
=> -4 ≤ x ≤ 4
This is partially in the range and partially not, so FALSE
(B) |x| ≤ 6
=> -6 ≤ x ≤ 6
This is partially in the range and partially not, so FALSE
(C) |x − 2| ≤ 4
=> -4 ≤ x - 2 ≤ 4
Adding 2 on all the sides we get
=> -4 + 2 ≤ x - 2 + 2 ≤ 4 + 2
=> -2 ≤ x ≤ 6
This is partially in the range and partially not, so FALSE
(D) |x − 1| ≤ 5
=> -5 ≤ x - 1 ≤ 5
Adding 1 on all the sides we get
=> -5 + 1 ≤ x - 1 + 1 ≤ 5 + 1
=> -4 ≤ x ≤ 6
This is partially in the range and partially not, so FALSE
(E) |x + 2| ≤ 4
=> -4 ≤ x + 2 ≤ 4
Subtracting -2 from all the sides we get
=> -4 - 2 ≤ x + 2 - 2 ≤ 4 - 2
=> -6 ≤ x ≤ 2
=> TRUE
So, Answer will be E
Hope it helps!
Playlist on Solve problems on Absolute Value here
Watch the following video to MASTER Absolute Values
