pgmat wrote:

One hour after Adrienne started walking the 60 miles from X to Y, James started walking from X to Y as well. Adrienne walks 3 miles per hour and James walks 1 mile per hour faster than Adrienne. How far from X will James be when he catches up to Adrienne?

A) 8 miles

B) 9 miles

C) 10 miles

D) 11 miles

E) 12 miles

Whats the best way to solve this problem? Is the distance from X to Y in the problem matter? Please give me detailed steps. Thank you.

This way looks time consuming. It isn't; took under a minute.

Travelers in same direction? B-->A-->

SUBTRACT rates. Use

\(\frac{D}{r}=t\) to find time taken to catch her. Finally, use time taken to find distance.

1. Find distance between them

Adrienne walked for one hour before James started. At 3 miles/hr * 1 hr, she walked 3 miles.

Three miles is the distance between them, the "gap."

2. Find combined or relative rate. This is a chase problem. They're walking in the

same direction, so

subtract their rates: (4-3) = 1 mi/hr

4. Find time for J to catch A from the distance and relative rate. D/r = t

At 1 mi/hr, for a distance of 3 miles it will take 3 mi/1 mph = 3 hours for him to catch her.

5. How far did James walk? rt= D

4 miles/hr * 3 hrs = 12 miles

Answer E

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